A bucket of water of mass m1 is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter d with mass m2. The cylinder pivots on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls a distance h to the water. You can ignore the weight of the rope.(adsbygoogle = window.adsbygoogle || []).push({});

I know the tension in the rope (T), the speed with which the bucket hits the water (v), and the time of the fall (t).

While the bucket is falling, what is the force exerted on the cylinder by the axle?

I am not really sure how to go about this problem. I have never solved any of its type before.

At first, I tried to do a free-body diagram of the windlass. The forces pointing down would be the weight of the windless and the tension force T. The normal force would be pointing up, and since the windlass itself is not moving linearly, I set N(normal force)=weight of windlass + tension. That didn't turn out to be correct, tho...

I just need a little clue to start me off...

Thanks so much!

Ryan

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# Homework Help: Falling bucket of water physics

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