What Torque Is Required to Raise a Water Bucket from a Well?

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Homework Help Overview

The problem involves calculating the torque required to raise a bucket of water from a well using a crank mechanism. The scenario includes a cylinder with a specified mass and diameter, and a bucket containing water with a known mass. Participants are exploring the implications of the given data and how it relates to the torque calculation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the mass of the cylinder and the torque calculation, with some questioning the relevance of the cylinder's mass when the bucket is raised at constant speed. There is also an exploration of the different torque values provided as potential answers.

Discussion Status

Some participants have expressed agreement with the original poster's approach, while others have noted that the mass of the cylinder may not be necessary for the specific scenario of constant speed. There is an acknowledgment of differing results among participants, indicating a productive exploration of the problem.

Contextual Notes

Participants mention the significance of significant figures in the provided numbers, which may influence the selection of the correct answer from the options given.

OierL
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Homework Statement


Water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a cylinder of mass 50 kg and diameter 25 cm. As you turn this cylinder with a crank, the rope raises the bucket. If the mass of a bucket of water is 20 kg, what torque must you apply to the crank to raise the bucket of water at a constant speed?

Solution:
a. 2.5 N.m
b. 24 N.m
c. 80 N.m
d. 2400 N.m
e. 49 N.m
I don't know which one is the correct solution and why they give me the data of the weight of the cylinder.

Homework Equations


∑F=m*a
∑M=F*r and ∑M=I*α

The Attempt at a Solution


If we raise the bucket at a constant speed, ∑M=0
-m(bucket)*g + T=m*α*r=0 (constant speed) ⇒ T=m*g
∑M= (-T*R) + (τ)=0 (Being τ the torque I apply) ⇒ -(m*g*R) + τ=0 ⇒ τ= 20 * 9,8 * (0,25/2)
τ=24,5N*m
 
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Your answer looks fine. The mass of the cylinder will be needed if the bucket has a given acceleration different from zero.
 
Your solution looks good to me. The mass of the cylinder was just to throw you off.
 
Ok thank you! Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
 
OierL said:
Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
The choice should be clear.
 
OierL said:
Ok thank you! Now I'll have to think which of the solutions choose, since my result is different from the others hahaha.
That should not be too hard. Note that the numbers are given to two significant figures.
 

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