FEA for Water Tank: Weight & Pressure Analysis

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Discussion Overview

The discussion revolves around the stress analysis of a water tank, specifically focusing on the application of weight and pressure in finite element analysis (FEA). Participants explore how to correctly account for the weight of the water and the pressure exerted at different heights within the tank.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about whether to apply the weight of the water in addition to the pressure at a given height or if the pressure already accounts for the weight.
  • Another participant suggests that only the pressure should be used in the analysis.
  • A participant provides a calculation example, stating that the pressure due to the water can be calculated using the formula ##p=\rho g h##, leading to a pressure of 9810 N/m² for a 1 m³ tank filled with water.
  • It is noted that the atmospheric pressure at the water surface should be added to the total pressure at the bottom unless gauge pressures are being used, in which case it may not be necessary.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether to include the weight of the water in addition to the pressure. There are competing views regarding the treatment of atmospheric pressure in the calculations.

Contextual Notes

Some assumptions regarding the definitions of pressure (absolute vs. gauge) and the specific conditions of the tank setup may not be fully articulated, leading to potential misunderstandings in the application of the concepts discussed.

Thomas Plank
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Hi,

I'm trying to do some stress analysis on a tank filled with water, I have split the walls into sections and applied the appropriate pressures. However, I'm confused as to whether I apply the weight of the water+pressure at that height difference to the bottom of the plate; or will the pressure account for the weight already? But this doesn't seem likely as the formula didn't include mass.

Thank you.
 

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You use the pressure only.
 
Thomas Plank said:
Hi,

I'm trying to do some stress analysis on a tank filled with water, I have split the walls into sections and applied the appropriate pressures. However, I'm confused as to whether I apply the weight of the water+pressure at that height difference to the bottom of the plate; or will the pressure account for the weight already? But this doesn't seem likely as the formula didn't include mass.

Thank you.

Assume a tank with an area of the bottom 1 m2 and a height of 1 m filled with water. The weight of the contained water then would be 1 m3 of water multiplied with its density ##\rho##, hence 1000 kg corresponding to 9810 N.

Now let's calculate the pressure due to the water: ##p=\rho g h = 1000 \cdot 9.81 \cdot 1 = 9810\;N/m^2##. The force on an area of 1 m2 then is 9810 N, which is exactly the force due to the weight of the water. To find a total pressure at the bottom of course one has to add the atmospheric pressure at the water surface.
 
stockzahn said:
Assume a tank with an area of the bottom 1 m2 and a height of 1 m filled with water. The weight of the contained water then would be 1 m3 of water multiplied with its density ##\rho##, hence 1000 kg corresponding to 9810 N.

Now let's calculate the pressure due to the water: ##p=\rho g h = 1000 \cdot 9.81 \cdot 1 = 9810\;N/m^2##. The force on an area of 1 m2 then is 9810 N, which is exactly the force due to the weight of the water. To find a total pressure at the bottom of course one has to add the atmospheric pressure at the water surface.
The atmospheric pressure doesn't have to be included if you're working with gauge pressures. Otherwise, you need to include the air pressure contribution from the outside of the tank as well.
 

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