ElfredaCyania
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I've just found a paper for this, the crater diameter for the same explosive charge D is proportional to g-1/6, which means a Martian crater is likely to be 1.176 times as big as an Earth one. According to the paper, its conclusion holds for buried and zero-depth charges, as well as the cohesionless soil of Mars. The soil used in the paper has a similar density to Martian soil. On page 3839 in 4.3 it mentioned the condition for a charge to crater. The optimal depth to crater is the critical depth dc, calculated using dc=C0/ρg, where C0is the cohesion (100-1000 Pa for Martian regolith, Chang et al.), ρ is density (1.37 as mentioned earlier), and g is Martian g, 3.71. The critical depth would vary between 20 m and 200 m. It is achievable with the current ground penetrators on the soft Martian sand but this doesn't say anything about the choice of yield.Astronuc said:Mars has a lower surface gravity, so one would have to bore deeper - more than double, and perhaps triple.
Crater efficiency is discussed on page 3835 but I haven't found numbers for nuclear bombs yet. But if we assume a nuclear bomb is somewhere between the explosives shown in Fig.1 and the sand is Ottawa sand (the most similar to the regolith) we may say the crater efficiency for 1e7 to 1e9 J bomb is around 101.5 or 30. And it can go as low as 15 at 1e11 J. This is a bad sign for nuclear detonation but only in terms of efficiency.
I agree that we lack the data for designing a nuclear detonation, for now. We need data for the underground structure of Mars (considering the depth we are targeting, a Borebot-like mission is required), the effect of explosives on Martian regolith (installing a bomb would be better but artificial impactors or observing existing crater will also do the job).Astronuc said:Before employing a nuclear device, one should determine the energy and explore a non-nuclear method for achieving such energy, e.g., from an impact of say 1 or 10 tonne accelerated into the Martian surface.
As for this, it highly depends on the mission design, like installed by the rover, penetrator bomb or delayed penetrator bomb. But for penetrators, after penetrating to a depth of around or more than 15 m, the soil would move back and rebound, burying the warhead (See page B-2 of the Mars Penetrator concept).Astronuc said:Er, what could go wrong?
For risk control, it would be similar to any controlled nuclear detonation or ground penetrator and it needs to be solved by engineering.
I said that because even a small bomb like the current active B61-12 in the US assets is 100 times more energetic than the 2021 63GJ event at its 1.5 kt configuration (50 times, considering the inferior efficiency of explosion compared to an earthquake, explained before). And for such a 1.5 kT bomb to be fully coupled, you only need a depth of 3.45m on Earth. (Maybe ~2.6 times on Mars, but I currently didn't find direct data to support this, the critical depth is 2.6 times for sure)Astronuc said:What yield is a 'very large fully-couple bomb'.
I would like to add that a nuclear detonation is a "very sharp, very brief, very powerful" seismic source according to Vidale from this report. Also, I would like to quote from the preface of Explosion Source Phenomenology: "Data from nuclear tests provide the most directly useful observations and constitute the most effective benchmarks for a quantitative evaluation of our forward-modelling capabilities.", particularly on a planet like Mars where significant geological activity is minimal. We are not able to rule out nuclear methods in deep seismology in the foreseeable future.
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