Few questions on Dirac's Principles of QM.

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The forum discussion centers on key concepts from Dirac's Principles of Quantum Mechanics, specifically addressing the Poisson quantic bracket, the significance of diagonal representations of observables, and the properties of Hermitian operators. The user seeks clarification on the implications of the equation \(\mathbf{p}=i\hbar\mathbf{d}\) and the physical meaning behind the conjugate transpose of differential operators. The responses highlight that Hermitian operators are essential for representing physical quantities and clarify the relationship between anti-Hermitian operators and their adjoints.

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Hi there,

I'm reading Dirac's Principles of QM, but I think I miss something...

1)When he derives the Poisson quantic bracket, he states that u_1v_1-v_1u_1=i\hbar[u_1,v_1] and says that hbar must be real since we introduced the imaginary unit. The thing is, since uv-vu is real, because we are talking about dynamics variable that are real linear operator, this means that [u,v] must be pure imaginary. But that doesn't fit well with what Dirac says a few lines below, where he hypothesizes that [u,v] in QM has the same value than in classical mechanic (and I derive from here that it is real).
What am I missing?

2)Why is so important a representation where the observables are diagonal? And why it is so important to build Schroedinger's representation?

3)I can't follow his derivation of the conjugate transpose of d/dq :
giving that \frac{d}{dq}\left.\psi\right>=\left.\frac{d\psi}{dq}\right>
<\psi\frac{d}{dq}=-<\frac{d\psi}{dq}
he makes these consideration: the conjugate transpose of \frac{d}{dt}\psi>\,\,\mathrm{is}\,\,<\frac{d\bar{\psi}}{dq} and, from the previous equation, <\frac{d\bar{\psi}}{dq}=-<\bar{\psi}\frac{d}{dq} hence the conjugate transpose of d/dq -d/dq.
My question is:why \bar{\frac{d\psi}{dq}>}=<\frac{d\bar{\psi}}{dq}? I thought that \forall |P>, \bar{|P>}=<P|and this gives \bar{\frac{d\psi}{dq}>}=<\frac{d\psi}{dq}
Again, what am I missing?

4) What does it mean that \mathbf{p}=i\hbar\mathbf{d}, where d is the translation operator? Better, what is the physical importance and meaning?

Thank you in advance, more questions coming :D
 
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I think much of your question is a result of terminology. Where you say a physical quantity needs to be represented by a "real linear operator", what you mean is Hermitian or self-adjoint. The Hermitian conjugate involves a complex conjugate and an order reversal, probably what you're calling conjugate transpose. Note that if u and v are Hermitian, then uv - vu will be anti-Hermitian. This explains the appearance of i in question 1.

It also explains question 3, since ∂/∂q is anti-Hermitian also. When you take the adjoint of ∂/∂q |ψ> you'll pick up a minus sign.
 
Ok, I get (probably) the answer to question (1), but not to the others.

Just to clarify: is the equation \overline{\alpha|P>}=<P|\overline{\alpha}(*) correct, the bar meaning taking the complex conjugate and alpha being an hermitian operator?
If so, then I can't understand why the following passage is right
\overline{\frac{d}{dq}\psi>}=\overline{\frac{d\psi}{dq}>}=<\frac{d\overline{\psi}}{dq}

If we consider in (*) |P>=dP/dq>, then it should be \overline{\frac{d\psi}{dq}>}=<\frac{d\psi}{dq} w/o the complex conjugate on psi.

Can it be this way:
\overline{\frac{d}{dq}\psi>}=<\psi\overline{\frac{d}{dq}}
\overline{\frac{d}{dq}\psi>}=\overline{\frac{d\psi}{dq}>}=<\frac{d\psi}{dq}=-<\psi\frac{d}{dq} hence \overline{\frac{d}{dq}}=-\frac{d}{dq}? (This demonstration is different from Dirac's but arrives to the same conclusion).
 

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