I Feynman's QED; 36,000 revolutions per inch for red light.

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Feynman's reference to 36,000 revolutions per inch for red light in "QED" relates to the wavelength of red light, approximately 1/36,000 inches (700 nm). This suggests a connection between the angle of the "little arrows," representing probability amplitudes of virtual photons, and the phase angle of electromagnetic oscillations in real photons. The discussion highlights the need for the QED model to align with classical electromagnetic wave behavior, particularly in phenomena like the double-slit experiment. The phase of the probability amplitude in QED must correspond to the frequency and wavelength of classical waves. This relationship remains a point of confusion, as Feynman did not provide further clarification.
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In Feynman's book, QED, The Strange Theory of Light and Matter, page 27 he says, "As long as the photon moves, the stopwatch hand turns (about 36,000 times per inch for red light); when the photon end up at the photomultiplier, we stop the watch."

I've been puzzling about the significance of 36,000. The wavelength of red light is about 1/36000 inches (700 nm). So it sounds like he is saying that the angle of the "little arrows" is the same as the phase angle of the EM oscillations in the photon. But my reading of the book is that the angle of the arrows refers to probability amplitudes of virtual photons, not the phase angle of a real photon. Feynman did not elaborate.

So I'm left confused. What is the significance of 36,000? Hopefully, an I-level answer is possible.
 
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anorlunda said:
I've been puzzling about the significance of 36,000. The wavelength of red light is about 1/36000 inches (700 nm). So it sounds like he is saying that the angle of the "little arrows" is the same as the phase angle of the EM oscillations in the photon. But my reading of the book is that the angle of the arrows refers to probability amplitudes of virtual photons, not the phase angle of a real photon. Feynman did not elaborate.
In Feynman's heuristic model it's both. If we take the double-slit, for example. The QED model must largely match the classical EM wave model. The phase of the probability amplitude must match the frequency/wavelength of the classical wave.
 
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