Field Intensity at Point X with A(q+) and B(q-): Solve the Question

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The discussion centers on calculating the electric field intensity at point X, which is equidistant from point A (q+) and point B (q-). The initial field intensity due to A(q+) is denoted as E. The correct approach to determine the resultant field intensity when B(q-) is introduced involves vector addition of electric fields. The consensus is that the resultant field intensity at point X is 0, as the fields from A and B cancel each other out.

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A point X is located equidistant from point A (q+) and B (q-) in a parallel plane.

If the field intensity of A(q+) at point X is E, then what would the new field intensity be if point B (Q-) is added?

A) 2E
B) 0
C) 1/2E
D) 3/4 E

I assumed the answer is 2E, since the field of the positive charge (A) plus the field of the negative charge (B) are combined, however, my friend says it's B and I'm not sure anymore. Please, help?
 
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Suzukigold said:
A point X is located equidistant from point A (q+) and B (q-) in a parallel plane.

If the field intensity of A(q+) at point X is E, then what would the new field intensity be if point B (Q-) is added?

I assumed the answer is 2E, since the field of the positive charge (A) plus the field of the negative charge (B) are combined …

Hi Suzukigold! :smile:

What do you mean by a parallel plane? :confused:

Any three points are in a plane.

Anyway, electric force is a vector field, so it obeys the law of vector addition, so you can't just add as if they were numbers. :smile:
 

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