Figuring out time when you have acceleration and distance.

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SUMMARY

The discussion centers on calculating the time required for a car to travel 30.0 meters while accelerating at a rate of 2.00 m/s². Participants agree that the initial velocity (vi) must be assumed to be 0 m/s for the problem to be complete. The relevant formula derived is t = √(2d/a), which is used to solve for time (t) based on the given distance and acceleration.

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How long does it take a car to travel 30.0m if it accelerates at a rate of 2.00m/s^2?
Given
Distance- 30.0m
A-2.00m/s^2

Do I need to find vi?
 
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You must need to assume it is initially at rest, otherwise the problem is incomplete.
 
1MileCrash said:
You must need to assume it is initially at rest, otherwise the problem is incomplete.

So now I have
Distance- 30.0m
a-2.00m/s^2
vi-0m/s
So can i now use the d=1/2at^2 formula?
But we're solving for t
making the equation t, taking the square root of 2d/a right?
 
Last edited:

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