Final momentum and velocity of 3kg object after 24N·s impulse

[princexcharles]

ok, i get this question that says:
"An object of mass 3.0 kg is moving in the neg. x direction with a speed of 2 m/s. it is acted upon by a force with an impulse of 24 N s. What is the final momentum and the final velocity after that impulse has acted on the object? so i did

P(initial) = mv
P = 3 x -2 = 6
J = (mv)final - (mv)initial
24 = (mv)final - (-6)
18 = mv
18 = (3.0)v
v = 6 m/s

so 18 is the final momentum and 6 is the final velocity?

 

[AKG]

Yes, that's right.

 

[M98Ranger]

Yes, your calculations are correct. The final momentum of the object would be 18 kg m/s in the negative x direction, and the final velocity would be 6 m/s in the same direction. This means that the object's speed increased from 2 m/s to 6 m/s due to the impulse of 24 N s. It is important to note that momentum is conserved in this scenario, meaning that the total momentum before and after the impulse remains the same. This is reflected in your calculation where the initial and final momentums add up to 24 kg m/s. Great job!