Final temperature of a gas passed through a porous plug

Click For Summary
SUMMARY

The discussion centers on calculating the final temperature of a gas undergoing a Joule-Thomson process as it passes through a porous plug. The gas is described by the equations of state P=U/V and T=3B(U^(2/3)/N^(1/3)V^(1/3)), with B as a constant. The fundamental equation of the Joule-Thomson effect, dT=(v/cp)(Tα-1)dP, is crucial for this calculation. The participant struggles to determine the heat capacity at constant pressure (Cp) and is advised to express enthalpy in terms of pressure and temperature using the equations of state.

PREREQUISITES
  • Understanding of the Joule-Thomson effect and its fundamental equation.
  • Familiarity with thermodynamic concepts such as enthalpy and heat capacity.
  • Knowledge of equations of state for gases, specifically P=U/V and T=3B(U^(2/3)/N^(1/3)V^(1/3)).
  • Ability to perform partial derivatives and manipulate thermodynamic equations.
NEXT STEPS
  • Research the derivation and application of the Joule-Thomson effect in real gases.
  • Study the relationship between enthalpy, pressure, and temperature in thermodynamic systems.
  • Learn how to calculate the heat capacity at constant pressure (Cp) for various gases.
  • Explore the implications of the Nernst Postulate in thermodynamics and its applications.
USEFUL FOR

This discussion is beneficial for students and professionals in thermodynamics, particularly those studying gas behavior in Joule-Thomson processes, as well as researchers focusing on heat capacity and enthalpy calculations.

Msilva
Messages
5
Reaction score
0

Homework Statement


A gas has the following equations of state: P=\frac{U}{V} \,\,\,and \,\,\,T=3B\frac{U^{\frac{2}{3}}}{N^\frac{1}{3}V^\frac{1}{3}}
where B is a positive constant. The system obeys the Nernst Postulate (S tends to zero as T tends to zero). The gas, at a initial temperature T_i and initial pressure P_i, is passed through a porous plug in a Joule-Thomson Process. The final pressure is P_f. Calculate the final temperature.

This question is from Callen, Thermodynamics (1985). Question 6.3-2

Homework Equations


The fundamental equation of Joule-Thomson effect is dT=\frac{v}{c_p}(T\alpha-1)dP (*)
Alpha is the coefficient of thermal expansion and Cp is the heat capacity at constant pressure.
I think that may be useful know the differential of enthalpy dH=TdS+VdP (assuming N constant)

The Attempt at a Solution


I tried to use the equations of state and write T=3B(\frac{P^2V}{N})^\frac{1}{3}
Then, isolating V in this expression, I tried to find alpha: \alpha=\frac{1}{v} \frac{\partial v}{\partial T} and replacing theese two values in the expression (*). My problem is that I didn't find the Cp.
Is my logic right? I can conclude by this way or am I completely wrong?
 
Physics news on Phys.org
You can work it this way, but as you noticed, it can take some work to get a useful expression for Cp.

Instead, you can try using what you know about enthalpy for the porous plug experiment. Can you use your equations of state to express enthalpy as a function of P and T?
 
  • Like
Likes   Reactions: Msilva and Chestermiller

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
30
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K