Find a 2x2 Matrix A for Given Eigenspaces E_2 and E_4

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SUMMARY

To find a 2x2 matrix A with specified eigenspaces E_4 = span [1, -1] and E_2 = span [-5, 6], one must utilize the relationship Av = (lambda)v, where lambda represents the eigenvalues. The matrix A can be expressed in the form A = C D C^{-1}, where C contains the eigenvectors and D is a diagonal matrix of eigenvalues. By substituting the eigenvectors into the equations derived from the eigenvalue relationships, four equations are generated, which can be solved to determine the elements of matrix A.

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  • Understanding of eigenvalues and eigenspaces in linear algebra
  • Familiarity with diagonalization of matrices
  • Knowledge of matrix multiplication and solving linear equations
  • Proficiency in using linear algebra notation and terminology
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  • Study the process of diagonalizing matrices, focusing on the construction of matrices C and D
  • Learn how to derive eigenvalues and eigenvectors from a given matrix
  • Practice solving systems of linear equations derived from matrix operations
  • Explore applications of eigenspaces in various fields such as physics and engineering
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Students and professionals in mathematics, particularly those studying linear algebra, as well as anyone involved in fields that require matrix computations and eigenvalue analysis.

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Find a 2\times 2 matrix A for which

E_4 = span [1,-1] and E_2 = span [-5, 6]

where E_(lambda) is the eigenspace associated with the eigenvalue (lambda)


relevant equations: Av=(lambda)v

The Attempt at a Solution



I've pretty much gotten most of the eigenspace/value problems down, but this one I'm clueless on how to work. Seems that you would have to work backwards , but I don't know how to do that.
 
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Suppose you have a matrix A and it is diagonalizable. That means you can write it as
[tex]A = C D C^{-1}[/tex]
When A is given, how can you construct the matrices C and D?

Once you answer this question, you'll also see the answer to your problem.
 
You can just do it directly. You are told that
[tex]\left(\begin{array}{cc}a & b \\ c & d\end{array}\right)\left(\begin{array}{c}1 \\ -1\end{array}\right)= 4\left(\begin{array}{c}1\\ -1\end{array}\right)= \left(\begin{array}{c}4\\ -4\end{array}\right)[/tex]
which gives you two equations for a, b, c, d and
[tex]\left(\begin{array}{cc}a & b \\ c & d\end{array}\right)\left(\begin{array}{c}-5 \\ 6\end{array}\right)= 2\left(\begin{array}{c}-5\\ 6\end{array}\right)= \left(\begin{array}{c}-10\\ 12\end{array}\right)[/tex]
which gives you another two equations. Solve those 4 equations.
 

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