Find a formula for 1, 3, 6, 10, 15, 21,

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SUMMARY

The sequence 1, 3, 6, 10, 15, 21 represents the triangular numbers, which can be expressed using the formula T_n = ∑_{i=1}^n i. This formula calculates the sum of the first n natural numbers, establishing a clear pattern in the sequence. The recursive definition a_{n+1} = a_n + n + 2, with a_0 = 1, also describes the sequence effectively. Understanding these formulas is crucial for solving similar problems involving triangular numbers.

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annoymage
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Homework Statement



find the formula for

1,3,6,10,15,21,...

Homework Equations



n/a

The Attempt at a Solution



i only can find n>=3

Tn = 3 + \sum i ; i=3 to n

help T_T
 
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For one thing, the numbers in the way you listed them are called a sequence. Do you see a pattern among those numbers? That may help you.
 
Last edited:


yea lol, it's sequence ;P sorry, and yea, i saw the pattern, but only start from 3 T_T
 


annoymage said:

Homework Statement



find the formula for

1,3,6,10,15,21,...

Homework Equations



n/a

The Attempt at a Solution



i only can find n>=3

Tn = 3 + \sum i ; i=3 to n
But 3= 1+ 2 and 1= 0+ 1 so you can say it is T_n= \sum_{i= 1}^n i That's a well known sum with a well known formula. Look up "triangular numbers".

help T_T
 


thanks, how come i didn't realized it's T_n= \sum_{i= 1}^n i instead of Tn = 3 + sum(i) ; i=3 to n.

thank you :D
 


There is no sigma notation in sequences, a sequence is written as:

<br /> \left \{a_{n} \right \}_{n=0}^{N}<br />

as to your sequence it could be defined by a recursive formula:

<br /> a_{n+1}=a_{n}+n+2<br />

<br /> a_{0}=1<br />
 

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