- #1

Petkovsky

- 62

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So what i did first was:

3^(2x+3) * 2^(2x+3) < 2^(x+7) * 3^(3x-1)

Now i don't know how to set up the equation. I guess this is not correct

2*(2x+3) < x+7 + 3x - 1

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- Thread starter Petkovsky
- Start date

- #1

Petkovsky

- 62

- 0

So what i did first was:

3^(2x+3) * 2^(2x+3) < 2^(x+7) * 3^(3x-1)

Now i don't know how to set up the equation. I guess this is not correct

2*(2x+3) < x+7 + 3x - 1

- #2

nicksauce

Science Advisor

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- #3

Petkovsky

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Find all values of x which satisfy the inequality. Sorry i didnt mention, i thought it was clear.

- #4

tiny-tim

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- #5

Gib Z

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Q: Find x such that; [tex]6^{2x+3} < 2^{x+7} \cdot 3^{3x-1}[/tex].

Rewrite the exponents on the RHS to also have 2x+3's, [tex] RHS = \frac{2^{2x+3}}{2^{x-4}} \cdot 3^{2x+3} 3^{x-4} = 6^{2x+3} \left( \frac{3}{2} \right)^{ x-4} [/tex].

The question is much easier in this form.

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