Find an equation for the horizontal tangent to the curve y=x-3root x (1 Viewer)

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r-soy

Hi

a ) find an equation for the horizontal tangent to the curve y=x-3root x
b) What is range of values of values of curve's slope ?
c ) What is range of values of curve ?

number a already I solved but my queation now in b and c

-----

I try to solve
b)
to get curve's slope must derivatives
range of values of values of curve's slope is ( - infinity , 1 ]
becuse when we put ( 0 ) in curve's slope It will comw 1

c ) did here put zero in y=x-3root x

Mark44

Mentor
Hi

a ) find an equation for the horizontal tangent to the curve y=x-3root x
What does 3root x mean?

Does it mean $$\sqrt[3]{x}$$

or $$3\sqrt{x}$$
?
b) What is range of values of values of curve's slope ?
c ) What is range of values of curve ?

number a already I solved but my queation now in b and c

-----

I try to solve
b)
to get curve's slope must derivatives
range of values of values of curve's slope is ( - infinity , 1 ]
becuse when we put ( 0 ) in curve's slope It will comw 1
What did you get for the derivative of this function?
c ) did here put zero in y=x-3root x

r-soy

I mean $$3\sqrt{x}$$

r-soy

I get for the derivative of this function?

3 X 1/2rootx

= 3/2rootx

Mark44

Mentor
I get for the derivative of this function?

3 X 1/2rootx

= 3/2rootx
No, that's not the derivative of y = x - 3x1/2

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