Find and P ((1-sqrt3 i)1-i) in Complex Analysis homework

Click For Summary

Homework Help Overview

The problem involves evaluating the expression (1 − √3 i)^(1−i) and understanding the notation P((1 − √3 i)^(1−i)) in the context of complex analysis. The original poster expresses confusion regarding the meaning of P.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the ambiguity of the notation P and question its standard use in mathematics. There is an attempt to evaluate the expression without the P notation, leading to further exploration of the components involved.

Discussion Status

The discussion is ongoing, with participants sharing their uncertainty about the meaning of P and exploring the evaluation of the expression itself. Some have provided insights into the evaluation process, but consensus on the meaning of P has not been reached.

Contextual Notes

There is mention of a lack of clarity in the textbook regarding the notation P, which may affect the understanding of the problem. Participants are also reflecting on previous homework assistance received.

nickolas2730
Messages
28
Reaction score
0
I have a homework question:
Find (1 − \sqrt{3} i)1−i and P((1 − \sqrt{3} i)1−i).

I don't know what does the P stand for, And i can't find it in the textbook either.

Thanks
 
Physics news on Phys.org
Welcome to PF, nickolas2730! :smile:

I have no clue what P stands for either.
I dare to say it is not a standard mathematical operator or function.
So you'll have to find it in your notes or else.
 
I like Serena said:
Welcome to PF, nickolas2730! :smile:

I have no clue what P stands for either.
I dare to say it is not a standard mathematical operator or function.
So you'll have to find it in your notes or else.

Thank you so much, i have handed it in already lol
and waiting for answer and see what on Earth does that P stand for
 
Let me know if you find out, will you? :wink:
 
sure!
btw, thanks for helping me for the homework question b4
 
P ((1 −√3i)1−i) = e(1−i)Log(1−√3i)
= e(1−i)(ln 2− ∏/3 i)
= eln 2−∏/3 e−(ln 2+∏/3)i
 
Funny.
This is just the evaluation of the expression.
Without P() it would say exactly the same.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
1K
Replies
2
Views
3K