Find Commutation Relation for [x_i, p_i^n p_j^m p_k^l] - Help Appreciated

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SUMMARY

The discussion focuses on finding the commutation relation for the expression [x_i, p_i^n p_j^m p_k^l]. The key takeaway is that the commutation relation can be derived using the fundamental relation [x_i, p_j] = iħδ_{i,j} and the recursive application of the product rule for commutators, [AB, C] = A[B, C] + [A, C]B. Specifically, the relation [x_i, p_i^n] is established as [x_i, p_i^n] = niħp_i^{n-1}, which serves as a foundational step towards solving the original problem.

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indigojoker
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i need to find the commutation relation for:

[x_i , p_i ^n p_j^m p_k^l]

I could apply a test function g(x,y,z) to this and get:

=x_i p_i ^n p_j^m p_k^l g - p_i ^n p_j^m p_k^l x_i g

but from here I'm not sure where to go. any help would be appreciated.
 
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You don't need a test function. All you need are the following:

(i) [x_i,p_j] = i \hbar \delta_{i,j}
(ii) [AB,C]=A[B,C]+[A,C]B
 
Last edited:
should that be [x_i,p_j] = i \hbar \delta_{i,j}?
 
i guess a more reasonable question would i expand [x_i,p_i^n]
 
If you use the second relationship in post #2 recursively, you will discover a general form for the commutator [x_i,p_i^n].
Try p^2 and p^3 first - you'll see what I mean.

PS: Yes, there was a "bad" minus sign which I've now fixed.
 
how about: [x_i,p_i^n]=ni \hbar p_i ^{n-1}
 
Looks good. Now you're just a step or two away from the answer to the original question.
 

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