Find Commutation Relation for [x_i, p_i^n p_j^m p_k^l] - Help Appreciated

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Homework Help Overview

The discussion revolves around finding the commutation relation for the expression [x_i, p_i^n p_j^m p_k^l], focusing on the properties of position and momentum operators in quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply a test function to the commutation relation but expresses uncertainty about the next steps. Some participants suggest using known commutation relations and properties of operators instead of a test function. There is a question regarding the correct form of the commutation relation [x_i, p_j]. Others propose expanding the commutator [x_i, p_i^n] and using recursive relationships to derive a general form.

Discussion Status

The discussion is active, with participants offering guidance on using known relationships and suggesting specific cases to explore. There is acknowledgment of a correction regarding a sign in the expressions. While some progress has been made towards understanding the commutation relations, explicit consensus on the final form has not been reached.

Contextual Notes

Participants are navigating the complexities of quantum mechanical operators and their commutation relations, with some assumptions about the properties of these operators being questioned. The discussion is framed within the context of homework help, indicating a focus on learning rather than providing direct answers.

indigojoker
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i need to find the commutation relation for:

[x_i , p_i ^n p_j^m p_k^l]

I could apply a test function g(x,y,z) to this and get:

=x_i p_i ^n p_j^m p_k^l g - p_i ^n p_j^m p_k^l x_i g

but from here I'm not sure where to go. any help would be appreciated.
 
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You don't need a test function. All you need are the following:

(i) [x_i,p_j] = i \hbar \delta_{i,j}
(ii) [AB,C]=A[B,C]+[A,C]B
 
Last edited:
should that be [x_i,p_j] = i \hbar \delta_{i,j}?
 
i guess a more reasonable question would i expand [x_i,p_i^n]
 
If you use the second relationship in post #2 recursively, you will discover a general form for the commutator [x_i,p_i^n].
Try p^2 and p^3 first - you'll see what I mean.

PS: Yes, there was a "bad" minus sign which I've now fixed.
 
how about: [x_i,p_i^n]=ni \hbar p_i ^{n-1}
 
Looks good. Now you're just a step or two away from the answer to the original question.
 

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