Find Continuous Functions Subject to an Integral Condition

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SUMMARY

The discussion focuses on identifying continuous functions \( f: [0,1] \to \mathbb{R} \) that satisfy the integral condition \( \int_0^1 f(t) \phi''(t) dt=0 \) for all test functions \( \phi \in C_0^{\infty}(0,1) \). The participants explore the implications of the Fundamental Lemma of the Calculus of Variations, particularly in scenarios where \( f \) is not differentiable. The conversation emphasizes the necessity of understanding variational principles to derive conclusions about the nature of such functions.

PREREQUISITES
  • Understanding of continuous functions and their properties
  • Familiarity with integral calculus and integration by parts
  • Knowledge of the Fundamental Lemma of the Calculus of Variations
  • Basic concepts of test functions in functional analysis
NEXT STEPS
  • Study the Fundamental Lemma of the Calculus of Variations in detail
  • Explore the properties of continuous functions on closed intervals
  • Investigate the implications of integration by parts in functional analysis
  • Learn about the space of test functions \( C_0^{\infty}(0,1) \)
USEFUL FOR

Mathematicians, particularly those specializing in functional analysis, calculus of variations, and anyone interested in the properties of continuous functions under integral constraints.

evinda
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Hello! (Wave)

I want to find all the continuous functions $f: [0,1] \to \mathbb{R}$ for which it holds that:$$\int_0^1 f(t) \phi''(t) dt=0, \forall \phi \in C_0^{\infty}(0,1)$$

If we knew that $f$ was twice differentiable, we could say that $\int_0^1 f(t) \phi''(t) dt= \int_0^1 f''(t) \phi(t) dt+ f(1) \phi'(1)-f(0) \phi'(0)$

What can we do if we are not allowed to differentiate $f$ ? (Thinking)
 
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