A wire of total length 34.00 m, consists of equal lengths of Cu followed by Al, both having the same diameter of 0.80 mm. A voltage difference of 86.0 V is placed across the composite wire. What is the current flowing in the wire? Use rho=1.72x10-8 ohm-m for the resistivity of copper and rho=2.82x10-8 ohm-m for the resistivity of aluminum.
RT = RCu + RAl
R = rho*L/(pi*r2)
R = V/I
The Attempt at a Solution
Solve R = rho*L/(pi*r2) for both Cu and Al and add together for RT
(34*1.72*10^(-8))/(pi*.04^2) + (34*2.82*10^(-8))/(pi*.04^2)
I = V/RT
= 280048.684 ohm
Keep getting the wrong answer, what am I doing wrong?