Find current flowing through the wire

  • Thread starter Sean1218
  • Start date
  • #1
86
0

Homework Statement



A wire of total length 34.00 m, consists of equal lengths of Cu followed by Al, both having the same diameter of 0.80 mm. A voltage difference of 86.0 V is placed across the composite wire. What is the current flowing in the wire? Use rho=1.72x10-8 ohm-m for the resistivity of copper and rho=2.82x10-8 ohm-m for the resistivity of aluminum.

Homework Equations



RT = RCu + RAl
R = rho*L/(pi*r2)
R = V/I

The Attempt at a Solution



Solve R = rho*L/(pi*r2) for both Cu and Al and add together for RT

(34*1.72*10^(-8))/(pi*.04^2) + (34*2.82*10^(-8))/(pi*.04^2)
= 0.000307089463

I = V/RT

86/0.000307089463
= 280048.684 ohm

Keep getting the wrong answer, what am I doing wrong?
 

Answers and Replies

  • #2
phyzguy
Science Advisor
4,949
1,890
Three things:

(1) If the total length is 34m, and it is made up of two pieces of equal length, how long is each piece?

(2) How many meters is 0.4mm?

(3) What are the units of current?
 
  • #3
86
0
Writing ohm was just a typo (was entering A before) and for some reason I was reading .80 mm as 80 mm, so I converted 80 mm -> .08 m. Completely forgot about halving the length though, thanks.

(17*1.72*10^(-8))/(pi*.0004^2) + (17*2.82*10^(-8))/(pi*.0004^2)
= 1.53544731

86/1.53544731
= 56.009737 A

That right then? I have one try left to get it right :s
 
  • #4
phyzguy
Science Advisor
4,949
1,890
That looks right to me.
 

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