# Find current using KVL (with dependent source)

1. Apr 15, 2015

### iharuyuki

1. The problem statement, all variables and given/known data

2. Relevant equations
V = IR
Kirchoff's Voltage Law
3. The attempt at a solution

Top loop - a
Bottom right - b
Bottom left - c
Ix = x

KVL:
top: a(6000) + (a-b)(2000) + 5x - 10=0
bottom right: -5x + (b-a)(2000) + b(3000) + (b-c)(4000) = 0
bottom left : 10 + (c-b)(4000) + c(2000) = 0
x = -c

x comes out to 2 mA when it should be 1.5. Where did I make a mistake?

Thank you very much.

2. Apr 16, 2015

### Staff: Mentor

How did you account for the given detail that $I_x$ is in mA?

3. Apr 16, 2015

### iharuyuki

got it! That was the error. The proper equations were this:

a(6000) + (a-b)(2000) + 5x - 10=0

-5x + (b-a)(2000) + b(3000) + (b-c)(4000) = 0

10 + (c-b)(4000) + c(2000) = 0

x/1000 = -c

Thank you very much!