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Find current using KVL (with dependent source)

  1. Apr 15, 2015 #1
    1. The problem statement, all variables and given/known data
    upload_2015-4-15_22-24-13.png

    2. Relevant equations
    V = IR
    Kirchoff's Voltage Law
    3. The attempt at a solution

    Top loop - a
    Bottom right - b
    Bottom left - c
    Ix = x

    KVL:
    top: a(6000) + (a-b)(2000) + 5x - 10=0
    bottom right: -5x + (b-a)(2000) + b(3000) + (b-c)(4000) = 0
    bottom left : 10 + (c-b)(4000) + c(2000) = 0
    x = -c

    x comes out to 2 mA when it should be 1.5. Where did I make a mistake?

    Thank you very much.
     
  2. jcsd
  3. Apr 16, 2015 #2

    gneill

    User Avatar

    Staff: Mentor

    How did you account for the given detail that ##I_x## is in mA?
     
  4. Apr 16, 2015 #3
    got it! That was the error. The proper equations were this:

    a(6000) + (a-b)(2000) + 5x - 10=0

    -5x + (b-a)(2000) + b(3000) + (b-c)(4000) = 0

    10 + (c-b)(4000) + c(2000) = 0

    x/1000 = -c

    Thank you very much!
     
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