Maximum power of circuit with dependent voltage source

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SUMMARY

The discussion focuses on calculating the maximum power of a circuit with a dependent voltage source using the equations V(oc) = I(sc) * R(th) and Kirchhoff's voltage law. The user successfully determined the short-circuit current (I(sc)) to be 0.2 mA and derived the Thevenin resistance (R(th)) as 2 kOhm. However, this value is 1 kOhm off from the expected answer, indicating a potential error in the loop equations or assumptions made during the analysis. The user seeks clarification on the discrepancies in their calculations.

PREREQUISITES
  • Understanding of Thevenin's theorem
  • Familiarity with Kirchhoff's voltage law
  • Basic circuit analysis techniques
  • Knowledge of dependent sources in electrical circuits
NEXT STEPS
  • Review Thevenin's theorem applications in circuit analysis
  • Study Kirchhoff's voltage law in more complex circuits
  • Learn about dependent voltage sources and their impact on circuit behavior
  • Practice solving circuit problems involving loop equations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in circuit analysis and design, particularly those working with dependent sources and Thevenin equivalents.

iharuyuki
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Homework Statement


upload_2015-4-16_7-58-20.png


Homework Equations


V(oc) = I(sc) * R(th)
Kirchoff's voltage law

The Attempt at a Solution


a) is okay. For part b):

After redrawing with the R(th) and V(th) found in part a):

Equations of loops:
s is I(sc)
a is I(left loop)

left loop:
-8 + a(4000) + (a-s)(4000) = 0

right loop:
(s-a)(4000) - (2000)x = 0

I(x):
a-s = x

I(sc) comes out to 0.2 mA
Then V(oc) = I(sc) R(th)
4 V = (0.002 A) R(th)
R(th) = 2 kOhm = R(L max)

However, this is 1 kOhm off from the answer.

What is the problem with the above working?

Thank you very much.
 

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All is good, thanks!
 
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