Find de Broglie Wavelength of 7.0 eV Electron

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SUMMARY

The discussion focuses on calculating the de Broglie wavelength of a 7.0 eV electron using the formula λ = h/p, where h is Planck's constant and p is momentum. Participants clarify that the kinetic energy (KE) of the electron can be equated to 7 eV, allowing the use of the non-relativistic kinetic energy formula KE = (1/2)mv² to solve for velocity (v). The confusion arises from the application of the photoelectric effect equation, which is deemed unnecessary for this problem. Ultimately, the correct approach involves directly using the energy of the electron to find its velocity and subsequently its wavelength.

PREREQUISITES
  • Understanding of de Broglie wavelength formula (λ = h/p)
  • Knowledge of kinetic energy equations (KE = (1/2)mv²)
  • Familiarity with electron mass (9.11 x 10^-31 kg)
  • Basic concepts of energy units (electronvolts, eV)
NEXT STEPS
  • Study the derivation and applications of the de Broglie wavelength formula.
  • Learn how to convert energy in electronvolts to joules for calculations.
  • Explore the implications of non-relativistic vs. relativistic kinetic energy equations.
  • Review the principles of the photoelectric effect and its relevance to electron behavior.
USEFUL FOR

Students and educators in physics, particularly those focusing on quantum mechanics and wave-particle duality, as well as anyone needing to understand electron behavior in various energy states.

Dart82
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Homework Statement


Find the de Broglie wavelength of a 7.0 eV electron.

Homework Equations


de Broglie wavelength = h/p = h/(mv)
Photoelectric effect equation (not 100% sure)

The Attempt at a Solution


i need to solve for v in de Broglie's equation so i can find the wavelength. i know the mass of the electron is 9.11x10^-31kg, i know that h is Plancks constant, and i know that the work function = 7.0 x (1.602x10^-19 J) BUT how can i find v?

I tried to find v by using the photoelectric effect equation but i didnt get a correct answer:
hf = KE + Work function...BUT how can i solve for v if i don't have the frequency!?
 
Last edited:
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The energy of the electron is just given by E=(1/2)*m*v^2 (no need for relativity here). Does that help?
 
Dick -
i wish i could tell you that it makes perfect sense now, but I'm still a bit confused here. When you say no relativity what exactly does that mean?
 
I mean the energy is low enough that the speed of the electron is much less than that of light. So I can use the nonrelativistic formula KE=(1/2)*m*v^2. Sorry to hear you are still confused, but why not just set 7eV equal to (1/2)*m*v^2 to find v?
 
Dick said:
Sorry to hear you are still confused, but why not just set 7eV equal to (1/2)*m*v^2 to find v?
well...i guess because i don't understand how the work function can just be set to equal the kinetic energy. how is it that the hf can just be dropped from the photoelectric equation? I sure do wish my teacher would have spent some more time on this stuff - it seems like he just left out half the info we need to complete this assignment.
 
Ok, i got the right answer but i only understand about 90% of what i did to get it. According the Photo. effect:
h*f - W = KE ...so then h*f - W = (1/2)mv^2
I guess my only question is where did the h and f disappear to?
 
Why do you think this is a photoelectric effect problem? There is no 'work function'. It's just a de Broglie wavelength problem.
 
Dart82 said:
Ok, i got the right answer but i only understand about 90% of what i did to get it. According the Photo. effect:
h*f - W = KE ...so then h*f - W = (1/2)mv^2
I guess my only question is where did the h and f disappear to?

There's no h*f in the problem either.
 
ok i see what you are saying. i guess because the only other place i have seen the eV is in the photoelectric effect problems. i have read my notes and the section in my book concerning the de Broglie Wavelength (which there were no examples problems given). consequently, i am having a tough time figuring out how to work them. The way i understand it P=mv, where v is the speed. i know KE = (1/2)mv^2. So in this instance KE = 7eV?
 
  • #10
Yes. In this case eV is just a unit of energy. I thought you were going to take a break.
 
  • #11
yes i am right now...
 
  • #12
Me too...
 

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