Find dy/dt for Y=2((x^2)-3x) when x=3

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Homework Help Overview

The problem involves finding the derivative dy/dt for the function Y=2((x^2)-3x) when x=3, given that dx/dt = 2. Participants are exploring the relationship between the derivatives and the values of x and t.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of dy/dx and the need to relate it to dy/dt. There is confusion regarding the appropriate value of x to substitute into the derivative and how dx/dt fits into the overall problem.

Discussion Status

Some participants have attempted to calculate dy/dx and are questioning how to proceed to find dy/dt. There is recognition of the need to substitute x=3 into the derivative, but uncertainty remains about incorporating dx/dt into the calculation.

Contextual Notes

Participants are grappling with the definitions and relationships between the derivatives, particularly how to transition from dy/dx to dy/dt while considering the given rate of change dx/dt.

RyanMcStylin
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Homework Statement


Suppose that Y=2((x^2)-3x) and dx/dt = 2
Find dy/dt when x=3

Homework Equations


the only calc is taking the derivative of the equation, i am wondering if i am doing the whole problem right.

The Attempt at a Solution


dy/dx = 4x-6
find the equation for x=3 and multiply in 2 for the rate of change of time
Y=4(2*3)-6
Y=18?

I think my answer goes back to the clac. I don't know what number i am supposed to plug in for X, i know it has to do when what X equals at dy/dt and the rate of chage of X over time.
 
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You found
\frac{dy}{dx}
(The derivative with respect to x when x=3.)

The problem is asking for
\frac{dy}{dt}
(The derivative with respect to t.)
 
RyanMcStylin said:

Homework Statement


Suppose that Y=2((x^2)-3x) and dx/dt = 2
Find dy/dt when x=3

Homework Equations


the only calc is taking the derivative of the equation, i am wondering if i am doing the whole problem right.

The Attempt at a Solution


dy/dx = 4x-6
find the equation for x=3 and multiply in 2 for the rate of change of time
Y=4(2*3)-6
Y=18?

I think my answer goes back to the clac. I don't know what number i am supposed to plug in for X, i know it has to do when what X equals at dy/dt and the rate of chage of X over time.

The problem SAYS "Find dy/dt when x= 3"! What value of x do you think you should put in? The phrase "what x equals at dy/dt" is meaningless.
 
i understand that 3 must be replaced for x, but where does the dx/dt = 2 fit into the equation? I am guessing around somewhere around the radius portion of the equation
 

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