Find Eigenvalues for $$y''+\lambda y=0$$

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    Eigenvalues
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Discussion Overview

The discussion revolves around finding the eigenvalues for the differential equation $$y''+\lambda y=0$$ with specific boundary conditions. Participants explore the nature of the eigenvalues, questioning whether they are complex or real, and delve into the implications of the characteristic equation and the cosine function.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that the eigenvalues are given by the relation $\cos{\sqrt{\lambda}}=2$, but questions whether these eigenvalues are complex.
  • Another participant corrects an earlier claim about the characteristic equation, stating it should be $m= \pm \sqrt{-\lambda}$ instead of $m= \pm \sqrt{\lambda}$.
  • There is a discussion about the range of the cosine function, which is noted to be $[-1,1]$, leading to the conclusion that the eigenvalues cannot be real if $\cos{\sqrt{\lambda}}=2$.
  • Participants explore the implications of expressing the cosine function in terms of complex exponentials, questioning how this affects the nature of $\lambda$.
  • One participant derives a quadratic equation from the cosine relation and discusses the implications for $e^{i \sqrt{\lambda}}$, leading to a discussion about the potential for $\lambda$ to be complex or real.
  • There is a suggestion that $\sqrt{-\lambda}$ must be complex, but uncertainty remains about how to conclude that $\lambda$ itself must be complex.
  • Another participant points out that when working with complex numbers, functions can become multivalued, complicating the analysis of $\lambda$.

Areas of Agreement / Disagreement

Participants express differing views on whether the eigenvalues are complex or real, with some arguing that $\lambda$ must be complex while others suggest it can still be real. The discussion remains unresolved regarding the definitive nature of the eigenvalues.

Contextual Notes

There are unresolved assumptions about the definitions of $\lambda$ and the implications of the boundary conditions. The discussion also highlights the complexity introduced by working with complex numbers and the multivalued nature of certain functions.

  • #31
I like Serena said:
That sounds very plausible. (Mmm)

Actually, $y=0$ is always a solution, regardless of the value of $\lambda$, so $\lambda=0$ is not really the corresponding eigenvalue.
So it makes sense to leave that one out.

Furthermore, the eigenfunctions for $-\ln^2(2\pm\sqrt 3)$ are identical.
That is because $$\frac 1{2-\sqrt 3} = 2+\sqrt 3$$.
So we might consider them as the same.

Great! (Whew)
I like Serena said:
Have you tried to calculate the Wronskian for 2 eigenfunctions of which 1 has an imaginary eigenvalue? (Wondering)

So should I try it for $u(x)=\sin{(x(-i \ln{(2+\sqrt{3})}+2 \pi n))}$ and $v(x)=v^*(x)=(2+\sqrt{3})^x-(2+\sqrt{3})^{-x}$ ?
 
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  • #32
mathmari said:
So should I try it for $u(x)=\sin{(x(-i \ln{(2+\sqrt{3})}+2 \pi n))}$ and $v(x)=v^*(x)=(2+\sqrt{3})^x-(2+\sqrt{3})^{-x}$ ?

Yes... (Sweating)
 
  • #33
I like Serena said:
Yes... (Sweating)

If I have done right the calculations, the Wronskian at $1$ is not equal to $0$! (Wink) (Party) (Dance)
 
  • #34
Thank you for your help! (Bow)
 

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