Find Force Exerted on Blocks Sliding Down a Rough Incline

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SUMMARY

The discussion focuses on calculating the acceleration and the force exerted by two blocks sliding down a rough incline. The blocks have masses of m1 = 2.500 kg and m2 = 3.100 kg, with coefficients of friction µ1 = 0.2300 and µ2 = 0.5100, respectively, on a 30.0-degree incline. The calculated acceleration of the blocks is 1.6336 m/s². Participants discuss the method of summing forces, including gravitational and frictional components, to derive the acceleration and the force exerted by the lighter block on the heavier block.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of friction coefficients and their application
  • Basic trigonometry for resolving forces on an incline
  • Familiarity with free-body diagrams
NEXT STEPS
  • Calculate the net force acting on each block using free-body diagrams
  • Explore the concept of frictional force in detail
  • Learn about inclined plane physics and its applications
  • Investigate the effects of varying incline angles on acceleration
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking to enhance their understanding of forces on inclined planes.

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Two blocks (m1 = 2.500 kg and m2 = 3.100 kg) slide down a rough 30.0 degree incline.
µ1 = .2300 for the lighter block
µ2 = .5100 for the heavier block
a) Determine the acceleration of the pair.



b) Calculate the force the lighter block exerts on the heavier one.

there is a picture as an attachment (couldn't figure out how to just put it on).

i think i have found the acceleration of the objects i got 1.6336 meter per second squared but i don't know how to find the force on the second object.

I took the sum of the forces which included (m1)(gravity)(sin30)-friction on that object + (m2)(gravity)(sin30)- friction of that object) all over (m1 + m2). to get 1.6886
 

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what work have you done so far? We can help put you in the right direction, but we won't do all of your work for you
 
i think i have found the acceleration of the objects i got 1.6336 meter per second squared but i don't know how to find the force on the second object.

I took the sum of the forces which included (m1)(gravity)(sin30)-friction on that object + (m2)(gravity)(sin30)- friction of that object) all over (m1 + m2). to get 1.6886
 
Last edited:

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