Find Force Exerted on Soccer Ball, Impulse Q Homework

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SUMMARY

The discussion focuses on calculating the average force exerted by a soccer player on a .45-kg soccer ball during a kick, which results in the ball reaching a maximum height of 2 meters and traveling a horizontal distance of 5 meters. The impulse equation, defined as Impulse = Favg (Delta T), is central to the solution, where Delta T is the duration of the kick at .04 seconds. To find the average force, participants need to determine the horizontal (Vx) and vertical (Vy) components of the initial velocity, which can then be used to calculate the final velocity (vf) and subsequently Favg using the formula Favg = mvf / Delta T.

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Homework Statement


Soccer player kicks stationary .45-kg ball to a teammate. The balls reaches a max height above ground of 2m at a horizontal distance 5m from the point where it was kicked. The duration of the kick was .04s. Neglecting aero drag, determine the magnitude of the average force the player exerted on the ball.

Homework Equations


Impulse = Favg (Delta T)

The Attempt at a Solution


I know how to solve the problem I just don't know how to get the components of velocity Vsuby and Vsubx. Just need help with that part, you'd solve for both velocities find the magnitude of the velocity, use the impulse equation plug and have Favg = mvf / Delta T.
 
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Can you solve the following projectile motion problem?

A ball is kicked so that it reaches max height of 2 m and travels a horizontal distance of 5 m. Find the horizontal and vertical components of the initial velocity. Neglect aero drag.
 

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