Find fundamental period of x(t) = cos(Pi * t)

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SUMMARY

The fundamental period of the function x(t) = cos(πt) is determined using the formula T = 2π/ω₀, where ω₀ is the angular frequency. For x(t) = cos(πt), ω₀ equals π, resulting in a fundamental period T of 2 seconds. Additional examples confirm the calculations for other functions, such as x(t) = cos(3πt) yielding T = 2/3 seconds and x(t) = sin(4πt) yielding T = 1/2 seconds. The discussion emphasizes the importance of correctly identifying the angular frequency to derive the period accurately.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Familiarity with angular frequency (ω₀) in periodic functions
  • Knowledge of the formula for calculating the fundamental period (T = 2π/ω₀)
  • Basic skills in mathematical notation and function analysis
NEXT STEPS
  • Study the derivation of the fundamental period for various trigonometric functions
  • Learn about the implications of angular frequency in different contexts
  • Explore the differences between sine and cosine functions in terms of phase shifts
  • Investigate the applications of periodic functions in real-world scenarios, such as signal processing
USEFUL FOR

Students in mathematics or physics, educators teaching trigonometric functions, and professionals in engineering or signal processing who require a solid understanding of periodic functions and their properties.

VinnyCee
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Homework Statement



Find fundamental period of x(t)\,=\,cos\left(\pi\,t\right)

Homework Equations



x(t)\,=\,A\,sin\left(\omega_0\,t\,+\,\phi\right)

Which has a fundamental period T\,=\,\frac{2\pi}{\omega_0}

The Attempt at a Solution



\omega_0\,=\,\pi <---- Right?

T\,=\,\frac{2\pi}{\pi}\,=\,2

T\,=\,2
 
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dextercioby said:
T=2 s. Don't forget the units.
"s"? What is "s"? The problem, as stated, does not have units- it is a pure function. Even if you assume "t" is time (I would not, I see no reason to assume this is a physics problem rather than a mathematics problem) why would you assume the units are seconds rather than minutes or hours?

In any case, VinnyCee, your analysis is correct.
 
Thanks for your help!

So, are the following correct?

x(t)\,=\,cos\left(3\,\pi\,t\right)\,\,\longrightarrow\,\,\omega_0\,=\,3\,\pi\,\,\longrightarrow\,\,T\,=\,\frac{2\,\pi}{3\,\pi}\,=\,\frac{2}{3}

x(t)\,=\,sin\left(4\,\pi\,t\right)\,\,\longrightarrow\,\,\omega_0\,=\,4\,\pi\,\,\longrightarrow\,\,T\,=\,\frac{2\,\pi}{4\,\pi}\,=\,\frac{1}{2}

x(t)\,=\,cos\left(\frac{\pi}{2}\,t\right)\,\,\longrightarrow\,\,\omega_0\,=\,\frac{\pi}{2}\,\,\longrightarrow\,\,T\,=\,\frac{2\,\pi}{\frac{\pi}{2}}\,=\,\frac{4\,\pi}{\pi}\,=\,4

x(t)\,=\,sin\left(\frac{\pi}{3}\,t\right)\,\,\longrightarrow\,\,\omega_0\,=\,\frac{\pi}{3}\,\,\longrightarrow\,\,T\,=\,\frac{2\,\pi}{\frac{\pi}{3}}\,=\,\frac{6\,\pi}{\pi}\,=\,6
 
Yes.
 

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