Find \(H(s)\) for Causal LTI System: Region of Convergence

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SUMMARY

The transfer function \(H(s)\) for the causal LTI system is determined to be \(H(s) = \frac{1}{s^2 + s + 1}\). The region of convergence (ROC) is specified as \(\text{Re} \{s\} < -\frac{1}{2}\), ensuring the system is both causal and stable. The derivation involves finding \(X(s)\) and \(Y(s)\) through the Laplace transform, leading to the conclusion that the inverse Laplace transform yields a sinusoidal response, confirming the system's characteristics.

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Dustinsfl
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Determine \(H(s)\) and specify its region of convergence. Your answer should be consistent with the fact that the system is causal and stable.

In order to find \(H(s)\), we need to find \(X(s)\) and \(Y(s)\).
\begin{align*}
x(t) &= Ri + L\frac{di}{dt} + \frac{1}{C}\int i(t)dt\\
X(s) &= \mathcal{L}\bigg\{i + \frac{di}{dt} + \int i(t)dt\bigg\}\\
&= I(s) + sI(s) - I(0) + \frac{1}{s}I(s)\\
&= I(s)\bigg(1 + s + \frac{1}{s}\bigg)\\
y(t) &= \frac{1}{C}\int i(t)dt\\
&= \mathcal{L}\bigg\{\int i(t)dt\bigg\}\\
&= \frac{1}{s}I(s)\\
H(s) &= \frac{\frac{1}{s}}{1 + s + \frac{1}{s}}\\
&= \frac{1}{s^2 + s + 1}
\end{align*}
View attachment 2097

What is a causal system?
For convergece, \(\text{Re} \ \{s\} < -\frac{1}{2}\) since the inverse Laplace of H is
\[
\frac{2}{\sqrt{3}}e^{-\frac{1}{2}t}\sin\Big(\frac{\sqrt{3}}{2}t\Big).
\]
 

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So a causal system is when
\[
\lim_{z\to\infty}H(z) < \infty
\]
 

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