MHB Find \(H(s)\) for Causal LTI System: Region of Convergence

  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    Lti System
Click For Summary
The transfer function \(H(s)\) for the causal LTI system is derived as \(H(s) = \frac{1}{s^2 + s + 1}\). The region of convergence (ROC) for this system is specified as \(\text{Re} \{s\} < -\frac{1}{2}\), ensuring stability. The inverse Laplace transform of \(H(s)\) results in a time-domain response of \(\frac{2}{\sqrt{3}}e^{-\frac{1}{2}t}\sin\Big(\frac{\sqrt{3}}{2}t\Big)\). A causal system is characterized by the condition \(\lim_{z\to\infty}H(z) < \infty\). This analysis confirms that the system is both causal and stable.
Dustinsfl
Messages
2,217
Reaction score
5
Determine \(H(s)\) and specify its region of convergence. Your answer should be consistent with the fact that the system is causal and stable.

In order to find \(H(s)\), we need to find \(X(s)\) and \(Y(s)\).
\begin{align*}
x(t) &= Ri + L\frac{di}{dt} + \frac{1}{C}\int i(t)dt\\
X(s) &= \mathcal{L}\bigg\{i + \frac{di}{dt} + \int i(t)dt\bigg\}\\
&= I(s) + sI(s) - I(0) + \frac{1}{s}I(s)\\
&= I(s)\bigg(1 + s + \frac{1}{s}\bigg)\\
y(t) &= \frac{1}{C}\int i(t)dt\\
&= \mathcal{L}\bigg\{\int i(t)dt\bigg\}\\
&= \frac{1}{s}I(s)\\
H(s) &= \frac{\frac{1}{s}}{1 + s + \frac{1}{s}}\\
&= \frac{1}{s^2 + s + 1}
\end{align*}
View attachment 2097

What is a causal system?
For convergece, \(\text{Re} \ \{s\} < -\frac{1}{2}\) since the inverse Laplace of H is
\[
\frac{2}{\sqrt{3}}e^{-\frac{1}{2}t}\sin\Big(\frac{\sqrt{3}}{2}t\Big).
\]
 

Attachments

  • Screenshot from 2014-03-11 22:17:34.png
    Screenshot from 2014-03-11 22:17:34.png
    1.8 KB · Views: 94
Mathematics news on Phys.org
So a causal system is when
\[
\lim_{z\to\infty}H(z) < \infty
\]
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 1 ·
Replies
1
Views
10K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K