MHB Find Inner Product for Quadratic Form in R^3

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SUMMARY

The discussion focuses on finding the inner product corresponding to the quadratic form $$=3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3}$$ in the vector space V=R^3. Participants emphasize the need to express this quadratic form in matrix notation as $$\mathbf{x}^T A \mathbf{x}$$, where A is a real symmetric positive definite matrix. The key step involves calculating the square root of matrix A, denoted as $$A^{\frac{1}{2}}$$, to establish the basis for the inner product.

PREREQUISITES
  • Understanding of quadratic forms in linear algebra
  • Familiarity with matrix representation of inner products
  • Knowledge of real symmetric positive definite matrices
  • Basic concepts of inner product spaces
NEXT STEPS
  • Learn how to derive the matrix representation of a quadratic form
  • Study the properties of real symmetric positive definite matrices
  • Explore the process of calculating the square root of a matrix
  • Investigate the implications of changing basis vectors in inner product spaces
USEFUL FOR

Mathematicians, students of linear algebra, and anyone interested in understanding quadratic forms and inner product spaces in R^3.

Denis99
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Let $$<x, x>=3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} $$ be a quadratic form in V=R, where $$x=x_{1}e_{1}+x_{2}e_{2}+x_{3}e_{3}$$ (in the base $${e_{1},e_{2},e_{3}}$$.
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?
 
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Denis99 said:
Let $$<x, x>=3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} $$ be a quadratic form in V=R, where $$x=x_{1}e_{1}+x_{2}e_{2}+x_{3}e_{3}$$ (in the base $${e_{1},e_{2},e_{3}}$$.
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?

what definition do you have to work with here? If it were me I'd iterate to the result-- start by encoding this with standard basis vectors, i.e.

$\langle x, x \rangle =3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} = \mathbf x^T A \mathbf x$

where $A$ is real symmetric positive definite. Then take the square root of $A$ and let that be your basis i.e. consider
$ A^\frac{1}{2} \mathbf x$
where the $kth$ column of $ A^\frac{1}{2} $ is denoted by $e_k$ in your text
 
steep said:
what definition do you have to work with here? If it were me I'd iterate to the result-- start by encoding this with standard basis vectors, i.e.

$\langle x, x \rangle =3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} = \mathbf x^T A \mathbf x$

where $A$ is real symmetric positive definite. Then take the square root of $A$ and let that be your basis i.e. consider
$ A^\frac{1}{2} \mathbf x$
where the $kth$ column of $ A^\frac{1}{2} $ is denoted by $e_k$ in your text

I have to work with definition like this one from definition of inner space in here
https://en.m.wikipedia.org/wiki/Inner_product_space
(in part Definition)
 
Denis99 said:
I have to work with definition like this one from definition of inner space in here
https://en.m.wikipedia.org/wiki/Inner_product_space
(in part Definition)

But I can't figure out how you could understand that and say this

Denis99 said:
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?

The reality is that one way or another you need to find $A^\frac{1}{2}$
 

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