Find Inner Product for Quadratic Form in R^3

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Discussion Overview

The discussion revolves around finding the inner product corresponding to a given quadratic form in \( \mathbb{R}^3 \). Participants explore definitions and methods related to inner product spaces, quadratic forms, and the representation of these concepts using matrices.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the quadratic form \( \langle x, x \rangle = 3x_{1}^2 + 2x_{2}^2 + x_{3}^2 - 4x_{1}x_{2} - 2x_{1}x_{3} + 2x_{2}x_{3} \) and asks how to find the corresponding inner product.
  • Another participant suggests encoding the quadratic form using standard basis vectors and expresses that the matrix \( A \) associated with the quadratic form is real symmetric positive definite.
  • There is a proposal to take the square root of matrix \( A \) to establish a new basis for the inner product space.
  • Some participants express confusion about the requirement to change variables in the quadratic form and seek clarification on the definitions being used.
  • References to definitions from external sources, such as Wikipedia, are made to support the discussion on inner product spaces.

Areas of Agreement / Disagreement

Participants express differing views on how to approach the problem, particularly regarding the definitions and methods for finding the inner product. There is no consensus on a single method or interpretation of the requirements.

Contextual Notes

Participants highlight the need to clarify definitions and assumptions related to inner product spaces and quadratic forms, but these remain unresolved within the discussion.

Denis99
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Let $$<x, x>=3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} $$ be a quadratic form in V=R, where $$x=x_{1}e_{1}+x_{2}e_{2}+x_{3}e_{3}$$ (in the base $${e_{1},e_{2},e_{3}}$$.
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?
 
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Denis99 said:
Let $$<x, x>=3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} $$ be a quadratic form in V=R, where $$x=x_{1}e_{1}+x_{2}e_{2}+x_{3}e_{3}$$ (in the base $${e_{1},e_{2},e_{3}}$$.
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?

what definition do you have to work with here? If it were me I'd iterate to the result-- start by encoding this with standard basis vectors, i.e.

$\langle x, x \rangle =3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} = \mathbf x^T A \mathbf x$

where $A$ is real symmetric positive definite. Then take the square root of $A$ and let that be your basis i.e. consider
$ A^\frac{1}{2} \mathbf x$
where the $kth$ column of $ A^\frac{1}{2} $ is denoted by $e_k$ in your text
 
steep said:
what definition do you have to work with here? If it were me I'd iterate to the result-- start by encoding this with standard basis vectors, i.e.

$\langle x, x \rangle =3x_{1}^2+2x_{2}^2+x_{3}^2-4x_{1}x_{2}-2x_{1}x_{3}+2x_{2}x_{3} = \mathbf x^T A \mathbf x$

where $A$ is real symmetric positive definite. Then take the square root of $A$ and let that be your basis i.e. consider
$ A^\frac{1}{2} \mathbf x$
where the $kth$ column of $ A^\frac{1}{2} $ is denoted by $e_k$ in your text

I have to work with definition like this one from definition of inner space in here
https://en.m.wikipedia.org/wiki/Inner_product_space
(in part Definition)
 
Denis99 said:
I have to work with definition like this one from definition of inner space in here
https://en.m.wikipedia.org/wiki/Inner_product_space
(in part Definition)

But I can't figure out how you could understand that and say this

Denis99 said:
Find the inner product corresponding to this quadratic form.

Is this that easy that you have to change '' second'' x-es for y (for example to write $$2x_{2}y_{3}$$ instead of $$2x_{2}x_{3}$$ at the end), or what I have to do?

The reality is that one way or another you need to find $A^\frac{1}{2}$
 

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