Find Integer Solutions for (A+3B)(5B+7C)(9C+11A)=1357911

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The forum discussion focuses on finding integer solutions for the equation \((A+3B)(5B+7C)(9C+11A)=1357911\). The primary approach involves determining the prime factors of 1357911, which are five in total, and subsequently forming all possible groups of three factors. This method is essential for identifying potential integer combinations that satisfy the equation.

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Find all integer solutions (if any) for the equation $(A+3B)(5B+7C)(9C+11A)=1357911$.
 
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I would start by finding the prime factors of 1375911 (there are five) then forming all groups of 3 factors.
 
Hi HallsofIvy!

Thanks for your reply. But since this is a challenge question, I hope you know our expectation here is to receive a full solution, no more, no less. (Happy)
 
No solution because

RHS is odd so all factors are odd so each term in the LHS is odd. there are 3 terms on the LHS and so their sum has to be odd.

but sum is 12A + 8B + 16C which is even so impossible
 

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