y' + y = e^x ; y(0) = 1(adsbygoogle = window.adsbygoogle || []).push({});

1st, i calculate the integrating factor...

u(x) = e^x

times the integrating factor with DE...

y'e^x + ye^x = e^2x

dy/dx e^x + ye^x = e^2x

d/dx ye^x = e^2x

ye^x = ∫ e^2x dx

.........= 1/2 e^2x + C

y = 1/2 e^x + C

the problem here, i didn't get the answer given which is..

y = 1/2 (e^x + e^-x)

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# Homework Help: Find integrating factor and solve the equation 3

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