Find Intersection of x=6,y=1+6t with X & Y Axes

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Discussion Overview

The discussion revolves around finding the intersection points of the lines defined by the equations x=6 and y=1+6t with the x and y axes. Participants explore the implications of these equations and the conditions under which intersections occur.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant notes that the x-intercept for the line x=6 is 6, as it is a vertical line, and states that there is no y-intercept since x cannot equal 0.
  • Another participant questions the role of the variable t in the equation y=1+6t, seeking clarification on its meaning and how it relates to finding intersections.
  • A participant expresses confusion about the necessity of the y=1+6t part and reflects on the process of determining intercepts, suggesting a misunderstanding of the approach.
  • One participant emphasizes the logical reasoning behind finding intercepts, questioning whether setting y=0 is necessary for finding the x-intercept.
  • A later reply clarifies that the original post implies two lines, but it is actually a single line represented in parametric form, reinforcing that the line does not cross the y-axis but does intersect the x-axis at (6, 0).
  • Another participant provides a general method for finding x and y intercepts from parametric equations, explaining the process of setting y=0 and x=0 to solve for t.
  • A participant expresses appreciation for the assistance provided by another member, acknowledging their patience and active participation.
  • A humorous remark is made about the challenges of online tutoring, highlighting the limitations of virtual communication.

Areas of Agreement / Disagreement

Participants generally agree on the x-intercept being at (6, 0) and the absence of a y-intercept for the line x=6. However, there remains some uncertainty regarding the interpretation of the variable t and the necessity of the y=1+6t equation in finding intercepts.

Contextual Notes

Some participants express confusion about the role of the parameter t and the method for finding intercepts, indicating a potential gap in understanding the relationship between the parametric equations and their graphical representation.

Who May Find This Useful

This discussion may be useful for students learning about parametric equations and their intersections with axes, as well as those seeking clarification on the interpretation of variables in mathematical contexts.

thomasrules
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Find the points where each of the following lines intersects the x and y axes,

x=6,y=1+6t

for some reason I don't know how to find the point. If I graph it I understand but I can't work it out.
 
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When you have x = 6, the x-intercept is automatically 6, because x = 6 is just a vertical line, so when y is 0, x must be 6. There is no y-intercept because the line never crosses the y-axis, this is because x cannot = 0.

What is the t supposed to be in y = 1+6t? A constant (number)? If 't' is a constant then you basically use the same idea.
 
mattmns said:
What is the t supposed to be in y = 1+6t? A constant (number)? If 't' is a constant then you basically use the same idea.

Ok I get everything from the beginning, and I know I'm retarded I should have understood that. What is making me confused is the y=1+6t part.

that comes from the vector equation r=(6,1)+t(0,6)

Why do you even need to know the y=1+6t part? How do you check from that? I originaly thought you needed to set x or y to zero...

BTW thanks
 
ok I completely Understand it now...But your explanation as well as mine is purely based on Logical reasoning. Don't you have to set y=0 to find an x intercept?
 
:wink: got it :D
 
Your original post: "Find the points where each of the following lines intersects the x and y axes" implies two different lines. Later you told us this was from r=(6,1)+t(0,6) which is a single line!
r= (6,1)+ t(0, 6) is the same as the parametric equations x= 6, y= 1+ 6t.

Since x is always 6, that line does not cross the y-axis. Of course, it crosses the x-axis at (6, 0).

In general, if you have parametric equations x= a+ bt, y= c+ dt, you find the x-intersept by setting y= 0, solve for t and use that value of t to find x. To find the y-intersept do the opposite: set x= 0, solve that equation for t and use that value of t to find y.
 
i just want to say. HallsoftIvy is a very patient and active tutor.

good work!
 
Who only screams and tears his hair occaisionally.

The real problem with the internet is that you can't use the two-by-four across the head and shoulders method!
 

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