MHB Find Length of Arc EF in Triangle ABC

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In triangle ABC, with angle A measuring 70 degrees and segment BC being 12 units, point O is the midpoint of BC. The circle centered at O with radius BO intersects lines AB and AC at points E and F, forming a right triangle ABF with angle ABF at 20 degrees. Consequently, angle EOF at the center is calculated as 40 degrees. The radius of the circle is determined to be 6 units, leading to the length of arc EF being approximately 4.1888 units. The solution is confirmed as correct and satisfactory.
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$\triangle ABC$,with $\angle A=70^o,$point $O$ is the midpoint of segment $\overline{BC}=12$
circle $O$(wth center $O$ and radius $\overline{BO})$, meets with $\overline{AB},\overline{AC}$ at points $E$ and $F$ respectively please find the length of arc $EF$
 
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Albert said:
$\triangle ABC$,with $\angle A=70^o,$point $O$ is the midpoint of segment $\overline{BC}=12$
circle $O$(wth center $O$ and radius $\overline{BO})$, meets with $\overline{AB},\overline{AC}$ at points $E$ and $F$ respectively please find the length of arc $EF$
[sp]
In the diagram, the angle $BFC$ is a right angle (angle in a semicircle). So $ABF$ is a right-angled triangle and $\angle ABF = 20^\circ$. Therefore $\angle EOF = 40^\circ$ (angle at centre = twice angle at circumference). If $BC$ is 12 units then the radius of the circle is 6 units, and the arc $EF$ is $2\pi\cdot 6\cdot\frac{40}{360} = \frac43\pi \approx 4.1888$ units.

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perfect ! very good solution !
 
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