Find Limiting Reactant: Homework Help

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Discussion Overview

The discussion revolves around identifying the limiting reactant in a chemical reaction involving NH2 and (CH3CO)2O, based on provided quantities and stoichiometric relationships. The context is homework help related to stoichiometry in a laboratory setting.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the quantities of reactants and the reaction equation, seeking guidance on how to determine the limiting reactant.
  • Another participant asserts that the limiting reagent is determined by the smallest number of moles available, concluding that (CH3CO)2O is the limiting reactant due to its lower mole count compared to NH2.
  • Some participants express uncertainty about the identity of NH2, with one suggesting it is an amino group and another questioning its existence as a separate entity.
  • There is a suggestion that the confusion may stem from a possible error in the information provided.

Areas of Agreement / Disagreement

Participants generally agree on the method of determining the limiting reactant based on mole quantities, but there is uncertainty regarding the identity and existence of NH2, leading to differing interpretations.

Contextual Notes

There are unresolved questions about the identity of NH2 and its role in the reaction, as well as potential errors in the provided information.

Saladsamurai
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Homework Statement



I have this information from a lab handout

I have:

.40g of NH2 = .25 mol NH2

.58g of (CH3CO)2O = .0092 mol (CH3CO)2O

and the reaction

NH2 + (CH3CO)2O---> HNCOCH3 + CH3COOH

I need to find the limiting reactant

I know that since the only product with N on the right hand side is HNCOCH3 so ALL of its N must have come from the NH2

I am just not sure how to "test" the reactant (CH3CO)2O ? Both products contain all of those elements?

Any thoughts?
 
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Because the entire equation reacts in a 1 to 1 ratio (all stoichiometric proportions are equal) your limiting reagent is the one with the smallest number of moles.
only 0.0092mol of (CH3CO)2O is available to react, and as the number of moles of NH2 that will react with it is in equal proportion (the 1:1 ratio), only 0.0092 of the 0.25 mol NH2 will ever react. Thus, the (CH3CO)2O is the limiting reagant

I may have oversimplified the question, but I hope this helps!
 
MustBe said:
Because the entire equation reacts in a 1 to 1 ratio (all stoichiometric proportions are equal) your limiting reagent is the one with the smallest number of moles.
only 0.0092mol of (CH3CO)2O is available to react, and as the number of moles of NH2 that will react with it is in equal proportion (the 1:1 ratio), only 0.0092 of the 0.25 mol NH2 will ever react. Thus, the (CH3CO)2O is the limiting reagant

I may have oversimplified the question, but I hope this helps!

No, I think it it a matter of me over complicating it! Thanks!

Casey
 
What is NH2?
 
Borek said:
What is NH2?

I'm not sure. But I think its an amino group and that because its a cation is available to attach as a amine to carbohydrates and such.
 
Trick is, such a thing doesn't exist as a separate entity.

My bet is that it was some kind of error, in copying or something.
 

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