Find Max Height for Basketball Throw: Is 9.8 Correct?

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SUMMARY

The discussion centers on calculating the maximum height a basketball can reach after being thrown downwards and bouncing back up. The player initially miscalculates using an incorrect formula involving multiple factors. The correct approach involves using the formula for free fall, specifically y = 1/2 * g * t², where g is the acceleration due to gravity (9.81 m/s²) and t is the time to reach maximum height (1.4 seconds). The maximum height can be accurately determined using this simplified method.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinematics.
  • Familiarity with the formula for free fall: y = 1/2 * g * t².
  • Knowledge of gravitational acceleration (g = 9.81 m/s²).
  • Ability to perform calculations involving time and distance in projectile motion.
NEXT STEPS
  • Study the principles of kinematics in physics to understand motion equations.
  • Learn how to apply the free fall formula in various scenarios.
  • Explore the effects of air resistance on projectile motion.
  • Investigate real-world applications of projectile motion in sports physics.
USEFUL FOR

Students studying physics, educators teaching kinematics, and sports analysts interested in the mechanics of basketball throws.

wadini
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Wrongly called for a foul, an angry basketball player throws the ball straight down to the floor if the ball bounces straight up and returns to the floor 2.8 s after first striking it, what was the ball's greatest height above the floor?

I keep getting the wrong answer I am plugging in (9.8)(1.4)(.5)(1.4)^2(9.81)

Am I anywhere close?
 
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wadini said:
Wrongly called for a foul, an angry basketball player throws the ball straight down to the floor if the ball bounces straight up and returns to the floor 2.8 s after first striking it, what was the ball's greatest height above the floor?

I keep getting the wrong answer I am plugging in (9.8)(1.4)(.5)(1.4)^2(9.81)

Am I anywhere close?

Welcome to PF.

Well ... looks like a few too many factors to have the right answer.

You know the time and so 1/2 will be time to max height ... you got that part.

But the distance it will fall in 1.4s is really given a bit more simply by

y = 1/2*g*t2
 

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