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## Homework Statement

An 1.94 m tall basketball player wants to make a basket from a distance d = 19.8 m. If he shoots the ball at θ = 58.7° angle, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard? The height of the basketball hoop is 3.05 m.

ΔH(y) = 1.11 m

d(x) = 19.8 m

θ = 58.7°

a(y) = -9.81 m/s^2

## Homework Equations

x(t) = X_0 + V_0x*t

v(y) = V_0y - g*t

v_f^2 = v_i^2 + 2a*d

## The Attempt at a Solution

0 = V_iy^2 + 2(-9.81)(1.11) → 4.66 m/s

0 = 4.66 + (-9.81)t → 0.475 s

V_0 = 4.66/sin(56.2) → 5.61 m/s

This is not the correct final answer and i am not sure where to even start with this problem