Find Min Energy of Particle Using Uncertainty Principle

Click For Summary
SUMMARY

The discussion focuses on calculating the minimum energy of a particle confined in a one-dimensional region using the Heisenberg Uncertainty Principle. The key equation derived is ΔxΔp = ħ/2, where Δx represents the uncertainty in position and Δp the uncertainty in momentum. For a 1g bead on a 10 cm wire, and for an electron in a 1 Å region, the minimum energy can be calculated using the relationship E = p²/2m. The participants emphasize the simplicity of the problem, indicating it is suitable for early quantum mechanics coursework.

PREREQUISITES
  • Understanding of Heisenberg Uncertainty Principle
  • Familiarity with basic quantum mechanics concepts
  • Knowledge of kinetic energy equations
  • Ability to perform calculations involving mass and length scales
NEXT STEPS
  • Calculate minimum energy for various particle masses using the Uncertainty Principle
  • Explore the implications of quantum confinement on energy levels
  • Learn about the relationship between momentum and energy in quantum systems
  • Investigate applications of the Uncertainty Principle in quantum mechanics
USEFUL FOR

Students in introductory quantum mechanics courses, physics educators, and anyone interested in the foundational principles of quantum theory and particle behavior.

darussiaman
Messages
7
Reaction score
0

Homework Statement



A particle of mass m is confined to a one-dimensional region of length a.
a.) use the uncertainty principle to obtain an expression for the minimum energy of the particle

b.) calculate the value of this energy for a 1g bead on a 10 cm wire, and for an electron in a region of 1 A in length.

Homework Equations



umm, as far as I'm aware, the only thing we're supposed to know is deltax*deltap => h-bar/2 and the energy-time analog of that. This is first of 3 semesters of quantum so we're not doing anything deep here, the needed equations on all the homework problems have so far been just the basic, simple ones so this shouldn't be any different...

The Attempt at a Solution



Well, I'm not sure how to set it up. This looks like it should be an easy question but having trouble for some reason. First, is this problem saying that deltax (uncertainty in position) is equal to a? If so, then the uncertainty in momentum is deltap => h-bar/(2a). OKay, so what? Energy ... well, kinetic energy = (1/2)*momentum*velocity ... so i could multiply both sides by that and would end up with uncertainty in energy on the left side, but velocity could be anything?? The delta_energy*delta time doesn't seem to be helpful either because what is change in time?
 
Physics news on Phys.org


Energy is momentum squared divided by twice the mass:

E=p^2/2m
 

Similar threads

Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
8K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
2K
Replies
2
Views
3K
Replies
3
Views
4K