1. The problem statement, all variables and given/known data Lauryl alcohol, C12H25OH, is prepared from coconut oil; it is used to make sodium lauryl sulfate, a synthetic detergent. What is the molarity of lauryl alcohol in a solution of 17.1g lauryl alcohol dissolved in 148g ethanol, C2H5OH? a) 0.310m b) 0.620m c) 0.842m d) 1.41m e) 2.52m Note: I'm not sure, but I think that the internet is allowed for this problem, in the sense that we can look up the densities of both the lauryl alcohol and the ethanol, because I see no way to solve this problem otherwise. (I can't solve it with the densities anyway) 2. Relevant equations n=m/M d=m/v 3. The attempt at a solution 1) There is 17.1g of C12H25OH molar mass of C12H25OH is 186.18g/mol number of moles of C12H25OH is 0.09185mol 2) There is 148g of C2H5OH molar mass of C2H5OH is 46.08g/mol number of moles of C2H5OH is 3.2118mol 3) The density, or (m/v) of C12H25OH is 0.8309g/mL (I used the internet for this step and the following) 4) The density, or (m/v) of C2H5OH is 0.789g/mL 5) This is where I start to feel unsure. 17.1g/v=0.8309g/mL v(C12H25OH)= 0.0206L 6) 148g/v=0.789g/mL v(C2H5OH)=0.1876L 7) total volume = 0.0206L + 0.1876L = 0.2082L 8) 0.09185mol/0.2082L = 0.4412m, which does not correspond with any of the answers.