Find molarity, seemingly simple but I can't do it.

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Discussion Overview

The discussion revolves around calculating the molarity of lauryl alcohol in a solution with ethanol, specifically addressing a homework problem that involves determining the concentration of lauryl alcohol based on given masses and densities. The conversation touches on concepts of molarity and molality, as well as the implications of volume additivity in solutions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The initial calculation of moles of lauryl alcohol and ethanol is presented, with molar masses provided for both substances.
  • One participant notes the importance of density in calculating volumes from mass, using internet sources for density values.
  • Concerns are raised about the assumption that the final volume of the solution is simply the sum of the individual volumes of lauryl alcohol and ethanol, with a reminder that volumes may not be additive when mixing different substances.
  • Another participant acknowledges a misunderstanding regarding the terms "molarity" and "molality," clarifying that the problem actually pertains to molality.
  • There is a suggestion to approach the problem by checking if the total mass and density of pure ethanol yield one of the provided answers, despite this not being a correct method in general.

Areas of Agreement / Disagreement

Participants express differing views on the correct approach to the problem, particularly regarding the treatment of volumes in the solution. There is no consensus on the best method to solve the problem, and the misunderstanding of terms adds to the complexity of the discussion.

Contextual Notes

Participants highlight limitations in the problem, such as the assumption of volume additivity and the distinction between molarity and molality, which may affect the calculations. The discussion does not resolve these issues.

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Homework Statement



Lauryl alcohol, C12H25OH, is prepared from coconut oil; it is used to make sodium lauryl sulfate, a synthetic detergent. What is the molarity of lauryl alcohol in a solution of 17.1g lauryl alcohol dissolved in 148g ethanol, C2H5OH?

a) 0.310m b) 0.620m c) 0.842m d) 1.41m e) 2.52m

Note: I'm not sure, but I think that the internet is allowed for this problem, in the sense that we can look up the densities of both the lauryl alcohol and the ethanol, because I see no way to solve this problem otherwise. (I can't solve it with the densities anyway)

Homework Equations



n=m/M
d=m/v


The Attempt at a Solution



1) There is 17.1g of C12H25OH
molar mass of C12H25OH is 186.18g/mol
number of moles of C12H25OH is 0.09185mol

2) There is 148g of C2H5OH
molar mass of C2H5OH is 46.08g/mol
number of moles of C2H5OH is 3.2118mol

3) The density, or (m/v) of C12H25OH is 0.8309g/mL (I used the internet for this step and the following)

4) The density, or (m/v) of C2H5OH is 0.789g/mL

5) This is where I start to feel unsure.
17.1g/v=0.8309g/mL
v(C12H25OH)= 0.0206L

6) 148g/v=0.789g/mL
v(C2H5OH)=0.1876L

7) total volume = 0.0206L + 0.1876L = 0.2082L

8) 0.09185mol/0.2082L = 0.4412m, which does not correspond with any of the answers.
 
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I don't see how to solve the problem more precisely, unless someone will find a table of densities of lauryl alcohol in ethanol solutions (don't waste your time trying too hard).

The only thing that is wrong is that you assumed final volume to be sum of both volumes - it will be not, as volumes are not additive*, BUT - for a given data, that's the best reasonable guess of what the final volume is. Check if ignoring volume of lauryl alcohol (that is, assuming final volume is that of ethanol - 187.6 mL) won't result in one of the given answers. If it does - that's what you were expected to do, sadly, that's not the correct approach. Alternatively, you can check if you will not get one of the answers given assuming total mass of 17.1+148 and density of pure ethanol - again, that won't give a correct answer in general, but it is one of the approximations used in such cases.

* If you combine two volumes of identical solution, volumes are additive - say, 50 mL of 1 M NaCl and 50 mL of 1 M NaCl gives 100 mL of 1 M NaCl. But when you mix different solutions or different substances, it won't work this way - 50 mL of water and 50 mL of ethanol yield 96.4 mL of a mixture. Differences are rarely large, but they do exist.

What you can be always sure about is that the final mass is the sum of both masses.
 
Borek - I appreciate your attempt to help, but I however made a mistake in reading the question.

Turns out "molality" was not a typo for "molarity" and the two mean different things.

My bad.
 
If it is about molality it is just plug and chug.
 

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