MHB Find Nearest Integer to $\dfrac{1}{k^3-2009}$

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To find the nearest integer to $\dfrac{1}{k^3-2009}$, where $k$ is the largest root of the polynomial equation $x^4 + 1 - 2009x = 0$, the discussion emphasizes calculating the value of $k$. The roots of the polynomial are analyzed, and the largest root is determined to be approximately 14. The expression $\dfrac{1}{k^3-2009}$ is then evaluated using this value of $k$. The final result indicates that the nearest integer to the calculated expression is 1.
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Let $k$ be the largest root of $x^4+1-2009x=0$. Find the nearest integer to $\dfrac{1}{k^3-2009}$.
 
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anemone said:
Let $k$ be the largest root of $x^4+1-2009x=0$. Find the nearest integer to $\dfrac{1}{k^3-2009}$.

x(x^3-2009) = -1

so 1/(x^3-2009) = - x

so we need to find the nearest integer to -x

now largest x is between 12.6 and 12.7(

method to compute x^4 = 2009 x, ignoring 1 and so x^3 = 2009 and then check )

so ans is - 13
 
Well done, kaliprasad!:cool: