Find number of turns in the solenoid

  • Thread starter jackxxny
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  • #1
jackxxny
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Homework Statement


I have the following information about the problem.

i have the speed of an electron = v
the diameter of a circular path = d
the length of a solenoid = x
the current that the solenoid carried = I

I need to find the number of turns in the solenoid.

Homework Equations



i used the following equations
QvB=v2m/r

B=[tex]\mu[/tex]NI/l

The Attempt at a Solution



then i put "B" in the first equation and i solve for N. Is that correct?
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
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Yes, do that.
 
  • #3
jackxxny
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the only weird thing is that i get a number like

.121

and it is not a turn .121??? or it can be a valid answer?
 
  • #4
rock.freak667
Homework Helper
6,223
31


the only weird thing is that i get a number like

.121

and it is not a turn .121??? or it can be a valid answer?

no, you can't really get less than one. Post the numbers and your working and we'll see if you went wrong anywhere.
 
  • #5
jackxxny
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v=1570 m/s
d = 1.57 cm
x = 35 cm
I = 2.61 A
what I did is :
N=(vmx)/(rQI*4*pi*10^-7)
 
  • #6
rock.freak667
Homework Helper
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I get the same answer as you, so I guess you'll need to put what you get and round up and put N=1
 
  • #7
jackxxny
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the problem really states....

....that the electron follows a circular path of diameter 1.57 cm near the center of an evacuated solenoid of length 35 cm .

does that changes anything?
 

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