Find ω, the angular frequency of oscillation of the object

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The discussion revolves around calculating the angular frequency (ω) of an oscillating object using the moment of inertia of a rod, which is defined as I=1/3ML^2. Participants clarify that ω can be derived from the equation ω=sqrt(g/L) and discuss how this relates to the hint provided, ω=sqrt(2mgd/I). There is confusion regarding the moment of inertia and its application, particularly since it hasn't been covered in the course. Ultimately, it is confirmed that the rod can be treated as uniform, and the calculations lead to a successful resolution of the problem. The conversation emphasizes the importance of understanding the moment of inertia in solving related physics problems.
joelkato1605
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Homework Statement
The first image is the question, and the second is the hint.
Relevant Equations
ω=sqrt(g/L)
I=1/3ML^2 ?
The hint says to use the moment of inertia of the rod, however i have not covered this on my course and I don't know what it is.
After googling moment of inertia of a rod I found that it is a quantity expressing a body's tendency to resist angular acceleration, and for a rod I=1/3ML^2.

So ω=sqrt(g/L) and the hint says ω=sqrt(2mgd/I), so how is 1/L=2md/I?
 

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HI,

Where does the $$ \omega = \sqrt{{g\over L}\ }$$ come from ?
Is it the full answer or is it just a hint and are you supposed to edit the expression by adding a coefficient ?

The Hint1 is correct; you can check it here (bearing in mind that the mass of your object is ##2m##).

I find it hard to believe that the exercise is given if moment of inertia hasn't been covered.
 
No sorry that's just what I typed as an initial guess but it was wrong.

Thanks that link was very helpful.

And the only time I have seen moment of inertia was in a example about stars rotating, and its value was just stated so I didn't know any formulas to find it.

So I=(2mL^2)/3, therefore I need to find what d equals, but it doesn't say the rod is uniform, so d= L*sqrt(2)/4, and then substitute and simplify.
 
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I think you have it all nicely lined up ! And yes, you may take the rod as uniform.
Hope it works !
 
Yeah it was correct, thanks for the help.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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