Find Optimal Distance from Wall for Max Angle of Vision

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SUMMARY

The discussion focuses on determining the optimal distance from a wall for an observer to maximize their angle of vision when viewing a picture that is 1.4 meters high and positioned 1.8 meters above the observer's eye level. The equation tan(θ + β) = (1.4 + 1.8) / x was proposed but deemed ineffective without a proper visual representation. Participants emphasized the importance of drawing a diagram to clarify the concept of "angle of vision" and its relation to the observer's position.

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  • Familiarity with basic geometry concepts, including angles and distances.
  • Ability to interpret and create geometric diagrams.
  • Knowledge of visual perception principles related to angles.
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  • Research the application of trigonometric functions in real-world scenarios.
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  • Explore the concept of angle of vision in optics and its mathematical implications.
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gangsterme
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A picture 1.4 meters high stands on a wall so that its lower edge is 1.8 meters above the eye of an observer. What is the most favorable distance from the wall for this observer to stand (that is, to maximize his or her angle of vision)?

I've tried using the tan (pheta+beta) = (1.4+1.8)/x equation
but it still doesn't work out...
 
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Draw a picture first! What is "angle of vision"? Show it in the picture!

ehild
 

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