Find potential energy of system with 3 charges

Click For Summary
SUMMARY

The potential energy of a system with three charges—q1 = 2 mC, q2 = 0.6 mC, and q3 = -1.5 mC—was calculated using the formula K( (q1*q2)/r + (q1*q3)/r + (q2*q3)/r). After correcting for the charge signs and ensuring the units were in milliCoulombs, the correct potential energy was determined to be -62402.4 J. The discussion highlighted the importance of considering the sign of charges in potential energy calculations.

PREREQUISITES
  • Coulomb's Law for calculating forces between charges
  • Understanding of electric potential energy concepts
  • Knowledge of unit conversions, specifically between microCoulombs and milliCoulombs
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of electric potential energy formulas
  • Learn about the implications of charge signs in electrostatics
  • Explore unit conversion techniques in physics
  • Investigate the applications of Coulomb's Law in real-world scenarios
USEFUL FOR

Students studying electrostatics, physics educators, and anyone looking to deepen their understanding of electric potential energy calculations in systems with multiple charges.

mbmcgee
Messages
7
Reaction score
0

Homework Statement



Three charges are at rest on the z-axis, q1 = 2 mC at z = 0 m, q2 = 0.6 mC at z = 1 m, and q3 = -1.5 mC at z = -0.4 m. What is the potential energy of this system?



Homework Equations





The Attempt at a Solution



Here is what i tried: K( (q1*q2)/r + (q1*q3)/r + (q2*q3)/r )

note: r is the distance between the two charges

Is this the right equation to use, and I just make a mathematical error?
If not, any suggestions on what to do?

-michael
 
Physics news on Phys.org
Hi michael,

mbmcgee said:

Homework Statement



Three charges are at rest on the z-axis, q1 = 2 mC at z = 0 m, q2 = 0.6 mC at z = 1 m, and q3 = -1.5 mC at z = -0.4 m. What is the potential energy of this system?



Homework Equations





The Attempt at a Solution



Here is what i tried: K( (q1*q2)/r + (q1*q3)/r + (q2*q3)/r )

note: r is the distance between the two charges

Is this the right equation to use, and I just make a mathematical error?
If not, any suggestions on what to do?

-michael

Your equation looks right to me; what numbers did you use in the equation, and what answer did you get?
 
alphysicist:
thanks for the reply

i got: K( (1.2E-12)/1 + (3E-12)/.4 + (9E-13)/1.4 )
which i ended up with 83,973.6 J somethings wrong lol
 
Last edited:
mbmcgee said:
alphysicist:
thanks for the reply

i got: K( (1.2E-6)/1 + (3E-6)/.4 + (9E-7)/1.4 )
which i ended up with 83,973.6 J somethings wrong lol

I believe you did not take into account that q3 is negative.
 
alphysicist said:
I believe you did not take into account that q3 is negative.

Ok, I reworked the problem with mC this time and took into account the -q3 but still get the wrong answer. I thought you were supposed to take the magnitude of the charges so I worked it that way but get a different but wrong answer.

edit: I edited the mC in my second post to be correct. I did not edit the answer.
 
mbmcgee said:
Ok, I reworked the problem with mC this time and took into account the -q3 but still get the wrong answer. I thought you were supposed to take the magnitude of the charges so I worked it that way but get a different but wrong answer.

edit: I edited the mC in my second post to be correct. I did not edit the answer.

So these are in microCoulombs and not milliCoulombs? If it is microCoulombs (and you don't want to use the symbol for micro) then it's better to write it as 2uC, for example, rather than 2mC.

What did you get for the answer?

(By the way, about using magnitudes: when calculating forces or fields with Coulomb's law you often only want to calculate the magnitude, because you can often get the direction from a force diagram. But for potential and potential energy calculations you keep the sign of the charges.)
 
alphysicist said:
So these are in microCoulombs and not milliCoulombs? If it is microCoulombs (and you don't want to use the symbol for micro) then it's better to write it as 2uC, for example, rather than 2mC.

What did you get for the answer?

(By the way, about using magnitudes: when calculating forces or fields with Coulomb's law you often only want to calculate the magnitude, because you can often get the direction from a force diagram. But for potential and potential energy calculations you keep the sign of the charges.)

Nevermind I am an idiot. It is milliCoulombs not micro. So once i took -q3 into account like you said i got the right answer which is -62402.4J. Thanks for the help.

My brain does not work to well so late at night :)
 
mbmcgee said:
Nevermind I am an idiot. It is milliCoulombs not micro. So once i took -q3 into account like you said i got the right answer which is -62402.4J. Thanks for the help.

My brain does not work to well so late at night :)

Glad to help! (And believe me I understand about those late nights and what they can do to your thinking.)
 

Similar threads

Replies
2
Views
1K
Replies
6
Views
1K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K