Find simplest differential equation

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Discussion Overview

The discussion focuses on finding the simplest differential equation that has specific solutions, particularly the functions \( y_p = \{\ln(x), e^x\} \). The scope includes theoretical exploration of differential equations, particularly linear homogeneous equations, and the implications of different forms and degrees of equations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about finding the simplest homogeneous differential equation given particular solutions.
  • Another participant suggests a specific linear homogeneous equation and describes a method to derive such equations from general solutions.
  • It is noted that \( e^x \) is a solution for \( y' = y \) and \( \ln(x) \) is a solution for \( y' = x - 1 \), leading to a proposed equation \( (y' - y)(y' - x - 1) = 0 \).
  • A method is proposed to derive coefficients \( p \) and \( q \) by substituting solutions into a general form of a second-order differential equation.
  • One participant questions the equivalence of different forms of differential equations that yield the same solutions, specifically comparing two proposed equations.
  • Another participant asserts that there are uncountably many ways to form differential equations with the given solutions if not restricted to linear homogeneous forms, providing examples of first and second-order ODEs.
  • It is mentioned that the form \( (y' - y)(y' - x - 1) = 0 \) can be generalized to include higher derivatives, leading to potentially many forms of differential equations with the same solutions.
  • A caution is raised that while a proposed differential equation may include the desired solutions, it could also introduce additional, unwanted solutions.
  • One participant clarifies that 'simplest DE' refers to linear differential equations rather than those of the lowest order.

Areas of Agreement / Disagreement

Participants express differing views on the nature and number of possible differential equations that can have the same solutions. There is no consensus on a single simplest form, and multiple competing models and approaches are presented.

Contextual Notes

The discussion includes various assumptions about the nature of differential equations, such as linearity and homogeneity, and the implications of introducing higher-order derivatives. The degree of a differential equation is also mentioned as a relevant factor, though its role remains unclear.

Who May Find This Useful

Readers interested in differential equations, particularly those exploring the relationships between solutions and the forms of equations, may find this discussion relevant.

epkid08
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How can I find the simplest differential equation given that I know the set of particular solutions? For example, take [tex]y_p=\{\ln(x), e^x\}[/tex], how can I find the simplest differential equation that has these solutions?

Edit: It has to be homogeneous.
 
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If it has to be linear homogeneous, then for example

(-x+x^2\ln(x))y''= (1+x^2\ln(x))y'-(x+1)y

Formal way to find LODE is as follow.
You can form the "general" solution as

y=C_1y_1+...+C_ny_n

and then eliminate C_1,...C_n by successive differentiations.
 
ex is a solution for y'=y.

ln(x) is a solution for y'=x-1.

Then [tex]y_p=\{\ln(x), e^x\}[/tex]

satisfy the DE (y'-y)(y'-x-1)= 0 :biggrin:
 
plug the solutions into a general form y''+p*y'+q*y=0 and you get two algebric equations which determines p and q.
 
Actually how many different ways can we form DE that has solutions y=e^x and y= ln x ?


Is my equation (y'-y)(y'-x-1)= 0 equivalent to (-x+x^2\ln(x))y''= (1+x^2\ln(x))y'-(x+1)y ?


I know a first order nonlinear Riccati DE can be reduced to a linear 2nd order DE. But not particularly sure of this one. Is the degree of a DE has any role to play?
Definition: The degree of a DE is the degree of the highest ordered derivative.
 
There are uncountable different ways to form DE (it'll be different DEs) that has solutions y=e^x and y= ln x if we do not restrict ourselves by homogeneous linear DEs. For example,

first order ODE
x*(exp(x)-ln(x))*diff(y(x),x)+(-exp(x)*x+1)*y(x)+(-1+x*ln(x))*exp(x)=0 ,

second order ODE
-ln(x)*x^2*(ln(ln(x))*ln(x)-1)*diff(y(x),x)^2-y(x)*x*(ln(x)+1)*diff(y(x),x)+y(x)*ln(x)*x^2*(ln(ln(x))*ln(x)-1)*diff(y(x),`$`(x,2))+factor(y(x)^2*ln(y(x))*ln(x)+y(x)^2*ln(y(x)))=0 .
 
Even just looking at the form (y' - y)(y' - x-1) = 0, there are any number of ways to form a differential equation with the given solutions, since Dn(ex) = ex, one can use (y(n) - y)(y' - x-1) = 0, for any positive integer n.
 
Last edited:
pbandjay said:
Even just looking at the form (y' - y)(y' - x-1) = 0, there are any number of ways to form a differential equation with the given solutions, since Dn(ex) = ex, one can use (y(n) - y)(y' - x-1) = 0, for any positive integer n.

You have to be careful, though. You proposed DE has introduced new solutions: [itex]\exp[\omega_n x][/itex], where [itex]\omega_n[/itex] is an n-th root of 1. So while such a DE does have the desired solutions, it now has many more, which may not be desired.
 
OK I will take note that 'simplest DE' means linear DE not the lowest order DE.
 

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