Find Solution for Polar to Rectangular Equation

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    Polar Rectangular
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SUMMARY

The discussion centers on converting the polar equation \( r = 1 - 2 \sin(\theta) \) into rectangular coordinates. The final rectangular form derived is \( x^2 + y^2 = \sqrt{x^2 + y^2} - 2y \). Participants confirm the accuracy of the transformation and discuss the implications of representing \( y \) as a function of \( x \). The conversation emphasizes the importance of understanding the graphical representation of polar equations.

PREREQUISITES
  • Understanding of polar coordinates and their conversion to rectangular coordinates.
  • Familiarity with trigonometric functions, specifically sine.
  • Knowledge of algebraic manipulation involving square roots and quadratic equations.
  • Graphing skills to visualize polar equations and their rectangular counterparts.
NEXT STEPS
  • Study the process of converting polar equations to rectangular form in detail.
  • Explore the graphical interpretation of polar equations using graphing software like Desmos.
  • Learn about the implications of polar equations in calculus, particularly in integration and area calculations.
  • Investigate the properties of conic sections as they relate to polar coordinates.
USEFUL FOR

Students of mathematics, educators teaching coordinate systems, and anyone interested in the graphical representation of equations in polar and rectangular forms.

karush
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Polar to rectangular

$$r=1-2 \sin\left({\theta}\right)$$

$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}+2y$$

Is this an answer just hard to get $y=$
 
Last edited:
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You've made a minor sign slip, but think of the graph of the polar equation...would you expect to get $y$ as a function of $x$?
 
$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final
 
karush said:
$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final

Yes, that looks good to me. :D
 

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