Find Solution for Polar to Rectangular Equation

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    Polar Rectangular
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Discussion Overview

The discussion revolves around converting a polar equation, specifically $$r=1-2 \sin\left({\theta}\right)$$, into its rectangular form. Participants explore the implications of this transformation and the challenges associated with isolating $y$ in the resulting equation.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant presents the polar equation and its rectangular form, questioning the difficulty in isolating $y$.
  • Another participant suggests that there may be a sign error and prompts consideration of the graph of the polar equation, questioning whether $y$ can be expressed as a function of $x$.
  • A subsequent post presents a modified rectangular equation, $$x^{2}+y^{2}=\sqrt{x^{2}+y^{2}}-2y$$, as a potential final form.
  • A later reply expresses agreement with the modified equation, indicating it looks good.

Areas of Agreement / Disagreement

There is some agreement on the modified rectangular equation, but the initial concerns about the sign and the ability to express $y$ as a function of $x$ indicate that the discussion remains somewhat unresolved.

Contextual Notes

Participants have not fully resolved the implications of the sign error or the conditions under which $y$ can be expressed as a function of $x$. The discussion reflects uncertainty regarding the transformation process.

karush
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Polar to rectangular

$$r=1-2 \sin\left({\theta}\right)$$

$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}+2y$$

Is this an answer just hard to get $y=$
 
Last edited:
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You've made a minor sign slip, but think of the graph of the polar equation...would you expect to get $y$ as a function of $x$?
 
$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final
 
karush said:
$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final

Yes, that looks good to me. :D
 

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