Find tension in this train coupling

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SUMMARY

The discussion focuses on calculating the tension in the coupling of a train consisting of a 100-tonne engine and 80-tonne trucks under two conditions: (a) with an acceleration of 0.020 m/s² and (b) at constant velocity. For part (a), the tension is determined to be 1,600 N, calculated using the formula F = m * a, where m is the mass of the trucks (80,000 kg). For part (b), the tension is 0 N, as there is no acceleration when moving at constant velocity. The calculations are confirmed to be correct, with a note on the units of tension.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m * a)
  • Basic knowledge of mass and acceleration units (tonnes to kg conversion)
  • Familiarity with concepts of force and tension in mechanical systems
  • Ability to differentiate between constant velocity and acceleration scenarios
NEXT STEPS
  • Study the implications of Newton's Laws in real-world applications
  • Learn about the dynamics of train systems and coupling mechanisms
  • Explore the effects of friction and resistance on train motion
  • Investigate advanced topics in mechanical engineering related to force transmission
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Students in physics or engineering, railway system designers, and anyone interested in the mechanics of motion and force in transportation systems.

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1. Homework Statement [/b

A railway engine of mass 100 tonnes is attahched to a line of trucks of total mass 80 tonnes. assuming there is no resistance to motion find the tension in the coupling between the engine and the leading truck (a) when the train has an acceleration of 0.020 ms/1^2
,(b) is moving at constant velocity. ( 1 tonne = 1.0 x 10^3 kg.)

Homework Equations



F= m*a

The Attempt at a Solution



for part (a) the tension in the coupling would be equal to the force acting on the train since the coupling is a device merely tranfering the force acting on the train to pull the trucks it is linked to. using force = mass * accelleration we can calculate the force of the train to be 80 000 kg *0.02 ms/s^2 which = 1.6 * 10^3 N. for part (b) the force acting on the couple would be 0 N since the velocity is constant there can be no acceleration because accelleration is the rate of change of velocity this implies that the force = 0 N since the acceleration = 0 m/s^2. mass * acceleration = force = 0 N are these answers right
 
Last edited:
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Yes they are right ( except for the units of Tension ).
 

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