Find the Area of the shaded region in the given problem

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SUMMARY

The discussion centers on calculating the area of a shaded region using geometric principles. The participant indicates that the textbook answer is 17.5, but they are seeking alternative methods to verify their calculations. They provide a formula involving variables such as S, α, and specific geometric dimensions, indicating a complex relationship between the area and trigonometric functions. The participant also mentions the sine of α as 1/3, which is crucial for solving the problem.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Familiarity with geometric area calculations.
  • Knowledge of algebraic manipulation and solving equations.
  • Ability to interpret and sketch geometric figures based on given parameters.
NEXT STEPS
  • Explore advanced trigonometric identities and their applications in area calculations.
  • Learn about the Law of Cosines and its relevance in solving geometric problems.
  • Investigate numerical methods for verifying area calculations, such as Monte Carlo integration.
  • Study the principles of calculus related to area under curves and shaded regions.
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Mathematics students, educators, and anyone involved in geometric problem-solving or seeking to enhance their understanding of area calculations in trigonometry.

chwala
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Homework Statement
See attached
Relevant Equations
Circular measure
Wawawawawa boggled me a little bit... but finally managed it...seeking alternative approach guys;

kindly note that what i have indicated as ##*## and a ##√## is the correct working ...

Text book answer indicates ##17.5## as answer... will re check my rounding solutions later...
1678364583516.png


My working- allow me to copy paste here...will later type the working...

1678364659756.png

1678364699766.png
 
Last edited:
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From your sketch, say S is area we want, it seems
2S=\frac{1}{2}*20^2 (4\alpha)-4*\frac{1}{2}*15\cos \alpha*5-2*\frac{1}{2}*5^2(\pi+2\alpha)
where
\sin\alpha =\frac{1}{3}
Is it same as your idea ?
 
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