Find the Area of the Shaded Section in a Circle

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SUMMARY

The discussion centers on calculating the area of a shaded section in a circle with a diameter of 10 cm. The area of the entire circle is calculated using the formula πr², resulting in an area of 78.54 cm². However, participants clarify that without knowing the angle between the rays defining the sector, it is impossible to determine the area of the shaded section. The conversation emphasizes the importance of distinguishing between diameter and circumference in mathematical contexts.

PREREQUISITES
  • Understanding of circle geometry, including radius and diameter
  • Familiarity with the area formula for circles: Area = πr²
  • Knowledge of angle measurement in radians or degrees
  • Ability to interpret geometric diagrams and relationships
NEXT STEPS
  • Explore the concept of circle sectors and their areas
  • Learn how to derive formulas involving angles in circles
  • Study the relationship between angles and arc lengths in circles
  • Investigate methods for estimating areas in geometric figures with incomplete information
USEFUL FOR

Students, educators, and anyone interested in geometry, particularly those looking to deepen their understanding of circle properties and area calculations.

M. M. Fahad Joy
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Known data:
IMG_20180529_180642.jpg

In the picture, CD = 10 cm. What is the area of shaded area?

Equation:
I know,
Area of a circle = ##πr^2##
Diameter of a circle = ##2πr##

Attempt:
Here, ## r = 10/2 = 5 ##
So, diameter ## = 2πr = 2*3.1416*5 = 31.42 cm ##
And area of the circle ## = πr^2 = 3.1416*5^2 = 78.54 cm^2 ##
But I don't know how to find out the area of sheded section.
Please help me.
 

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M. M. Fahad Joy said:
View attachment 226609
In the picture, CD = 10 cm. What is the area of shaded area?

I know,
Area of a circle = ##πr^2##
Diameter of a circle = ##2πr##

Here, ## r = 10/2 = 5 ##
So, diameter ## = 2πr = 2*3.1416*5 = 31.42 cm ##
And area of the circle ## = πr^2 = 3.1416*5^2 = 78.54 cm^2 ##
But I don't know how to find out the area of sheded section.
Please help me.
You don't have enough information to get a numerical value for this area, as it depends on the angle between the two rays that define the circle sector. The best you can do is to get an expression that involves this angle.
 
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Mark44 said:
You don't have enough information to get a numerical value for this area, as it depends on the angle between the two rays that define the circle sector. The best you can do is to get an expression that involves this angle.
Can I get the value of AB?
 
M. M. Fahad Joy said:
Can I get the value of AB?
No, not without knowing that angle. You can write an expression that involves the angle, but you can't get a numerical value without knowing the angle.
 
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Mark44 said:
No, not without knowing that angle. You can write an expression that involves the angle, but you can't get a numerical value without knowing the angle.
It means it is an unanswerable question. Isn't it? It is a question from creative talent hunt.
 
M. M. Fahad Joy said:
It means it is an unanswerable question. Isn't it? It is a question from creative talent hunt.

Perhaps they want you to supply some additional information, or create a question of your own! For example, if you let ##x## be the length of segment AB, you can try to develop formulas for the shaded area and the angle DOA in terms of ##x##. Alternatively, you can assume that ##y## is the angle DOA and then try to develop a formula for ##x## or for the shaded area.
 
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Or maybe they were hoping you would give the range of possible values for the shaded area. You could give its min and max possible values quickly without solving for the area in terms of the angle.
 
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LCKurtz said:
Or maybe they were hoping you would give the range of possible values for the shaded area. You could give its min and max possible values quickly without solving for the area in terms of the angle.
But how? Would you give me hint?
 
M. M. Fahad Joy said:
But how? Would you give me hint?
Try drawing the figure with angle AOB smaller. A lot smaller. Then larger. How small and large can it get? What happens to the shaded area when you do it?
 
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  • #10
LCKurtz said:
Try drawing the figure with angle AOB smaller. A lot smaller. Then larger. How small and large can it get? What happens to the shaded area when you do it?
0° to 360°
0 sq. cm to 78.54 sq. cm
Right or not?
 
  • #11
Right.
 
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  • #12
M. M. Fahad Joy said:
Known data:
View attachment 226609
In the picture, CD = 10 cm. What is the area of shaded area?

Equation:
I know,
Area of a circle = ##πr^2##
Diameter of a circle = ##2πr##

Attempt:
Here, ## r = 10/2 = 5 ##
So, diameter ## = 2πr = 2*3.1416*5 = 31.42 cm ##
And area of the circle ## = πr^2 = 3.1416*5^2 = 78.54 cm^2 ##
But I don't know how to find out the area of sheded section.
Please help me.

Note: the diameter of the circle is just ##2r= 10##cm in this case. The circumference is ##2 \pi r##! You must distinguish between diameter and circumference; otherwise, you will lose marks on exams.
 
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  • #13
Ray Vickson said:
Note: the diameter of the circle is just ##2r= 10##cm in this case. The circumference is ##2 \pi r##! You must distinguish between diameter and circumference; otherwise, you will lose marks on exams.
Sorry, It was a fault of my translation into English.

LCKurtz said:
Right.
Thanks for your help.
 

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