Find the compositions of these functions?

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SUMMARY

The discussion focuses on the composition of two functions, f(x) = x² + 3 and g(x) = |x| - 5, specifically analyzing gf(x). The calculated composition gf(x) = x² - 2 is confirmed as accurate. It is established that the range of gf(x) is not the same as the range of g(x); while the range of g(x) is [-5, ∞), the range of gf(x) is [-2, ∞). The reasoning provided clarifies that the range of gf is a subset of the range of g, emphasizing that the two functions are distinct and their ranges do not equate.

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Given two functions , f(x)=x^2+3 , where x is real , g(x)=|x|-5 , x is real , find gf(x).

i found gf(x)=x^2-2

is it true that the range of gf(x) is the same as the range of g(x) ? If so,

the range of g(x) is [-5 , infinity) and the range of gf(x) is [-2 , infinity)

why arent they the same ?
 
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I think everything is correct, why would you think the range of g(f(x)) is the same as the range of g(x)?
 


I'll pose the reverse question: why should they be the same? g(x) and gf(x) are different functions.
 


Take a look at the diagram i attached . Isn't that the image of gf(x) the same as the image function g(x) ?
 


The range of f needn't be the whole of the domain of g so some of the images under g may not occur in gf. You only have range(gf)\subseteq range(g). In fact you could say they're not equal because you have yourself provided a counterexample.
 


Martin Rattigan said:
The range of f needn't be the whole of the domain of g so some of the images under g may not occur in gf. You only have range(gf)\subseteq range(g). In fact you could say they're not equal because you have yourself provided a counterexample.

thanks Martin , how about the domains , is the domain of f(x) the same as domain gf(x) because both of them started from the same set or it needn't also be the same in this case.
 


Yes, dom(gf)=dom(f), assuming you only define the composition gf when range(f)\subseteq dom(g).
 


Martin Rattigan said:
Yes, dom(gf)=dom(f), assuming you only define the composition gf when range(f)\subseteq dom(g).

thanks again Martin !
 

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